1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
denis-greek [22]
3 years ago
7

How much potential energy does a 40-N medicine ball gain when it is lifted 5 m?

Physics
1 answer:
777dan777 [17]3 years ago
6 0
We know, Potential Energy = Force * Height
Here, F = 40 N
h = 5 m

Substitute their values, 
U = 40 * 5
U = 200 J

In short, Your Answer would be Option A

Hope this helps!
You might be interested in
A parallel plate capacitor fully charged to voltage V is connected to the battery (the voltage on the plates remains fixed). If
Papessa [141]

Charge will decreases.

A parallel plate capacitor when it is fully charged to voltage V is given as:

                    C = Q/V

The capacitance of parallel plate capacitor with two plates of Area A separated by distance d and no dielectric material between plates is

                    C = ε₀ A /d

since from above equation it shows C is proportional to Q and also C is inversely proportional to distance d.

So, ATQ when d increases C will decrease which in result decreases charge on the capacitor.

Thus,  Charge will decrease.

Learn more about capacitance here:

     brainly.com/question/17115454

          #SPJ4

7 0
2 years ago
If stellar parallax can be measured to a precision of about 0.01 arcsec using telescopes on the Earth to observe stars, to what
marin [14]

Answer:

It corresponds to a distance of 100 parsecs away from Earth.

Explanation:

The angle due to the change in position of a nearby object against the background stars it is known as parallax.

It is defined in a analytic way as it follows:

       

\tan{p} = \frac{1AU}{d}

Where d is the distance to the star.

p('') = \frac{1}{d} (1)  

Equation (1) can be rewritten in terms of d:

d(pc) = \frac{1}{p('')} (2)

Equation (2) represents the distance in a unit known as parsec (pc).

The parallax angle can be used to find out the distance by means of triangulation. Making a triangle between the nearby star, the Sun and the Earth (as is shown in the image below), knowing that the distance between the Earth and the Sun (150000000 Km), is defined as 1 astronomical unit (1AU).

For the case of   (p('') = 0.01):

d(pc) = \frac{1}{0.01}

d(pc) = 100

Hence, it corresponds to a distance of 100 parsecs away from Earth.

<em>Summary:</em>

Notice how a small parallax angle means that the object is farther away.

Key terms:

Parsec: Parallax of arc second

7 0
3 years ago
What are the effects of gravity on earth?​
Sliva [168]

Answer:

Without it, we could not survive on Earth. Earth orbits the sun due to the gravity of the sun, which maintains us at a convenient distance from it to enjoy the sun's warmth and light. It keeps the air we need to breathe and our atmosphere in place. Our planet is held together by gravity.

5 0
1 year ago
Read 2 more answers
How long does it take for a train to increase its velocity from 10m/s to 40m/s if it accelerates at 3 m/s
DIA [1.3K]

Answer:

Explanation:

Givens

Vi = 10 m/s

Vf = 40 m/s

a = 3 m/s^2

Formula

a = (vf - vi) /t              Substitute the givens into this formuls

Solution

3 = (40 - 10) / t          Multiply both sides by t

3*t = t(40 - 10)/t        Combine. Cancel t's on the right

3*t = 30                     Divide by 3

3t/3 = 30 / 3

Answer: t = 10 seconds.

6 0
2 years ago
A super snail initially traveling at 2 m/s accelerates at 1 m/s^2 for 5 seconds. How fast will it be going at the end of the 5 s
Vedmedyk [2.9K]

Answer:

The snail travel at the end of 5 s with a velocity of 12 m/s and the distance of the snail is 22.5 m.

Explanation:

Given that, the initial velocity of the snail is,

u=2m/s

And the acceleration of the snail is,

a=1m/s^{2}

And the time taken by the snail is,

t=5 sec

Now according to first equation of motion,

v=u+at

Here, u is the initial velocity, t is the time, v is the final velocity and a is the acceleration.

Now substitute all the variables

v=2m/s+ 1 \times 5 sec\\v=7m/s

Therefore, the snail travel at the end of 5 s with a velocity of 7 m/s.

Now according to third equation of motion.

v^{2}- u^{2}=2as\\ s=\frac{v^{2}- u^{2}}{2a} \\

Here, u is the initial velocity, a is the acceleration, s is the displacement, v is the final velocity.

Substitute all the variables in above equation.

s=\dfrac{7^{2}- 2^{2}}{2(1)}\\s=\dfrac{45}{2}\\ s=22.5m

Therefore the distance of the snail is 22.5 m.

4 0
2 years ago
Other questions:
  • Protons and neutrons in an atom are held together by _____.
    11·1 answer
  • A kayaker moves 22 meters northward, then 18 meters southward , and finally 24 meters northward what is the distance and magnitu
    15·1 answer
  • A hollow sphere of radius 0.200 m, with rotational inertia I = 0.0484 kg·m2 about a line through its center of mass, rolls witho
    12·1 answer
  • A (blank) is a point on a standing wave that appears to be stationary
    6·1 answer
  • Which of the following types of technologies has best helped scientists to study very high-energy objects in outer space, such a
    15·2 answers
  • 23.
    15·1 answer
  • What type of circuit is pictured?<br> O Parallel Circuit<br> Series Circuit
    13·2 answers
  • Formula for percentage error​
    7·1 answer
  • A rocket that has a mass of 4000 lbm travels at 27,000 ft/sec. What is most nearly its kinetic energy
    12·1 answer
  • Energy is the capacity to do work or
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!