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3 years ago

How much potential energy does a 40-N medicine ball gain when it is lifted 5 m?

1 answer:

6 0

We know, Potential Energy = Force * Height
Here, F = 40 N
h = 5 m

Substitute their values,
U = 40 * 5
U = 200 J

In short, Your Answer would be Option A

Hope this helps!

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ASK YOUR TEACHER Red blood cells often can be charged. Two red blood cells are separated by 1.11 m and have an attractive electr

makvit [3.9K]

Answer:

q2 = -1.61*10^-5 C.

Explanation:

It was given that,

F = 0.985N

q1 = +8.40 X10-6 C

q2 = ?

r = 1.11 m

k = 9 x 10^9 (standard)

It generally follows that, if force is attractive, charge will be negative.

force, F = kq1q2/r^2

0.985 = 9*10^9*8.40*10^-6*q2/1.11^2

75600q2 = 0.985*1.11^2

75600q2 = 1.2136

q2 = 1.2136/75600 = 1.60529

q2 = -1.61*10^-5 C.

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3 years ago

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Study the image below. What interaction causes the water to spread as they pass through the rock opening?

Kamila [148]

I think is diffracton.

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3 years ago

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A soccer ball of mass 0.35 kg is rolling with velocity 0, 0, 1.8 m/s, when you kick it. Your kick delivers an impulse of magnitu

Mademuasel [1]

Answer:

position 9.58 m

Explanation:

In impulse exercises and amount of movement, we always assume that the contact time is small,

I = Δp

With this expression we can calculate the final speed

I = m Vf - m Vo

Vf = (I + mVo) / m

Vf = (1.8 + 0.35 1.8) /0.35

Vf = 6.94 m / s

To calculate the acceleration of the ball we use Newton's second law, after finishing the impulse

∑ F = m a

fr = m a

a = fr / m

a = -0.26 / 0.35

a = -0.74 m/s²

A negative sign indicates that this acceleration is slowing the ball

Now we have speed and time acceleration, so we can use the kinematic equations to find the position at 1.5 s

X = Vo t + ½ to t²

In this case Vo is the speed with which the ball comes out after the impulse 6.94

X = 6.94 1.5 + ½ (-0.74) 1.522

X = 9.58 m

7 0

3 years ago

What is newton's second law also give example

neonofarm [45]

$\textbf{Question:-}$

What is newton's second law of motion?Also give example.

$\textbf{Answer:-}$

Definition:-

Newton's Second Law of motion states that the rate of change of momentum of an object is proportional to the applied unbalanced force in the direction of the force. ie., F=ma.

Examples:-

When you are kicking a ball, you are increasing the speed by applying force to it. Therefore,it accelerates.
If you use the same force to push a truck and push a car, the car will have more acceleration than the truck.

Derivation:-

For a body of mass 'm' , whose velocity changes from u to v in time t, when Force 'F' is applied.

=>Force∝Change in momentum/Time

=>F∝mv-mu/t

=>F∝m(v-u)/t

=>F∝ma

=>F=kma(a=v-u/t)

=>F=ma(Since k=constant=1)

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3 years ago

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A force of 50n is applied to an object at an angle of 50 degrees measured relative to the horizontal. Determine the horizontal a

kobusy [5.1K]

Answer:

Fx = 32.14 [N]

Fy = 38.3 [N]

Explanation:

To solve this problem we must decompose the force vector, for this we will use the angle of 50 degrees measured from the horizontal component.

F = 50 [N]

Fx = 50*cos(50) = 32.14 [N]

Fy = 50*sin(50) = 38.3 [N]

We can verify this result using the Pythagorean theorem.

$F = \sqrt{(32.14)^{2}+ (38.3)^{2}} \\F = 50 [N]$

3 0

3 years ago