All categories

3 years ago

Why does the lens need to be thicker for viewing nearby objects?

1 answer:

5 0

Answer: To focus on a near object – the lens becomes thicker, this allows the light rays to refract (bend) more strongly. To focus on a distant object – the lens is pulled thin, this allows the light rays to refract slightly.

Explanation:

You might be interested in

On his way to class, a student on a skateboard is accelerating on a downhill stretch. Which of the following statements is true?

sasho [114]

Answer:

B is correct

Explanation:

Because of gravity

3 0

3 years ago

What must be attached to each carburetor on a gasoline inboard engine?

alekssr [168]

To each carburetor on a gasoline inboard engine a backfire flame arrestor must be attached.This arrestor will prevent flames from the backfire causing a fire on board. Several things are important in order the backfire arrestor to function properly:
- should be clean and undamaged.
- If there is a hole in the grid, or oil or gasoline in the grid, or if it is not properly attached, the arrestor will not work correctly.
- must be approved by the U.S. Coast Guard

3 0

3 years ago

If an object is being pulled by two forces, one 4 N to the left and the other 2 N to the right, what is the net

nika2105 [10]

Answer:

Explanation:

subtract rthe two forces to see which is greater

4-2=2

6 0

3 years ago

How do your results from ray tracing compare to your results from using the thin-lens equation?

EastWind [94]

Answer:

20cm

Explanation:

A convex lens has a positive focal length and the object placed in front of it produce both virtual and real image (image distance can be negative or positive depending on the nature of the image).

According to the lens equation

$\frac{1}{f} = \frac{1}{u} + \frac{1}{v}$ where;

f is the focal length of the lens

u is the object distance

v is the image distance

If the magnification is - 0.6

mag = v/u = -0.5

v = -0.5u

since v = 10cm

10 = -0.5u

u = -10/0.5

u =-20 cm

Substitute u = -20cm ( due to negative magnification)and v = 10cm into the lens formula to get the focal length f

$\frac{1}{f} = \frac{1}{u} + \frac{1}{v}\\\frac{1}{f} = \frac{1}{-20} + \frac{1}{10}\\\frac{1}{f} = \frac{1}{-20} + \frac{1}{10}\\\frac{1}{f} = \frac{-1+2}{20} \\\frac{1}{f} = \frac{1}{20} \\cross \ multiply\\f = 20\\f = 20 cm$

Hence the focal length of the convex lens is 20cm

7 0

3 years ago

A centrifuge was used to separate into it’s components. What conclusions out the sample can be formed based on the technique use

Tatiana [17]

-- The sample was a fluid.

-- It was a mixture or a suspension ... NOT a solution.

4 0

3 years ago