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3 years ago

Why does the lens need to be thicker for viewing nearby objects?

1 answer:

5 0

Answer: To focus on a near object – the lens becomes thicker, this allows the light rays to refract (bend) more strongly. To focus on a distant object – the lens is pulled thin, this allows the light rays to refract slightly.

Explanation:

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What is the average power output of an athlete who can life 9.0 * 10^2 kg 2.5 m in 2.0 s?

eduard

Answer:

Average power output of athlete = 11025 Watts

Explanation:

Work done is defined as the product of force applied and the displacement perpendicular to the force.

Work = $Force\times Displacement$

Power is defined as work done per unit time.

Power = $\frac{Work done}{Time}$

Here the person lifts 900 kg.

Height = 2.5 m

Time interval = 2 seconds

Force = $weight \times gravity$

= $900 \times 9.8$

= 8820 N

Work done = $Force\times Displacement$

= $8820 \times 2.5$

= 22050 J

Power = $\frac {22050}{2}$

= 11025 Watt

3 0

3 years ago

The probability of breaking a tree branch increases

inessss [21]

Answer:

Its due to moment of force. Explanation: Possibility of breaking the branch increases when a person goes to the tip of the branch due to moment of force. Due to moment of force, branch tend to bend downward when we go at the tip of branch.

Explanation: Hope that helps broski

3 0

3 years ago

A motorcyclist drives around a bend with a 20 m radius, with a constant velocity of 3 m/s. The motorcyclist and the motorcycle h

Pavel [41]

Answer:

$a=0.45\ m/s^2$

Explanation:

Given that,

The radius of a bend, r = 20 m

Velocity of motorcyclist, v = 3 m/s

The combined mass of motorcyclist and the motorcycle is 50 kg

We need to find the motorcyclist’s centripetal acceleration. The formula used to find the centripetal acceleration is given by :

$a=\dfrac{v^2}{r}\\\\a=\dfrac{(3)^2}{20}\\\\a=0.45\ m/s^2$

So, the acceleration of the motorcyclist is $0.45\ m/s^2$ .

3 0

3 years ago

Maximum current problem. If the current on your power supply exceeds 500 mA it can damage the supply. Suppose the supply is set

VikaD [51]

To solve this problem we will apply Ohm's law. The law establishes that the potential difference V that we apply between the ends of a given conductor is proportional to the intensity of the current I flowing through the said conductor. Ohm completed the law by introducing the notion of electrical resistance R. Mathematically it can be described as

$V = IR \rightarrow R = \frac{V}{I}$