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3 years ago

15

The ________ on the axis (c2) forms a pivot point with the atlas (c1) that allows you to nod a "no."

1 answer:

grandymaker [24]3 years ago

3 0

The dens or the odontoid process of the axis or the second cervical spine forms a pivot point with the atlas or the first cervical vertebrae that is responsible for the nodding and the rotational movements of the head. This is reinforced by ligaments and the atlanto-occipital joint that allows the head to make a nodding or up and down movement on the vertebral column.

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The loudness of sound is determined by what?

baherus [9]

The amplitude of a sound<span> wave </span>determines<span> its </span>loudness<span> or volume. A larger amplitude means a louder </span>sound<span>, and a smaller amplitude means a softer </span><span>sound</span>

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2 years ago

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A bowling ball has a mass of 50 kg and is traveling with a velocity of 18 m/s 4 points

IRISSAK [1]

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2 years ago

Atoms of the same element can have different properties.<br><br> A) True<br><br> B) False

vladimir2022 [97]

Answer:

False.

Explanation:

All atoms of the same element have the same number of protons, but some may have different numbers of neutrons.

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2 years ago

A straight wire of length 0.53 m carries a conventional current of 0.2 amperes. What is the magnitude of the magnetic field made

olga55 [171]

Explanation:

It is given that,

Length of wire, l = 0.53 m

Current, I = 0.2 A

(1.) Approximate formula:

We need to find the magnitude of the magnetic field made by the current at a location 2.0 cm from the wire, r = 2 cm = 0.02 m

The formula for magnetic field at some distance from the wire is given by :

$B=\dfrac{\mu_oI}{2\pi r}$

$B=\dfrac{4\pi \times 10^{-7}\times 0.2\ A}{2\pi \times 0.02\ m}$

B = 0.000002 T

$B=10^{-5}\ T$

(2) Exact formula:

$B=\dfrac{\mu_oI}{2\pi r}\dfrac{l}{\sqrt{l^2+4r^2} }$

$B=\dfrac{\mu_o\times 0.2\ A}{2\pi \times 0.02\ m}\times \dfrac{0.53\ m}{\sqrt{(0.53\ m)^2+4(0.02\ m)^2} }$

B = 0.00000199 T

or

B = 0.000002 T

Hence, this is the required solution.

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3 years ago

I need help please answer fast!!!

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2 years ago