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bija089 [108]
3 years ago
15

a car begins at rest at a stoplight. After the light turns green, the car begins to accelerate 5 m/s squared over the span of 3.

6 seconds. What is the car's displacement over this period of time
Physics
1 answer:
gogolik [260]3 years ago
4 0

Answer: 9m

Explanation:

Our given:

Acceleration- 5m/s^2

Time- 3.6 seconds

Use the equation d = 1/2 • a • t^2

d = 1/2 • 5m/s^2 • 3.6 secs

d = 2.5m/s^2 • 3.6 secs

d = 9m

I hope this is correct

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b

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Explanation:

Generally from third equation of motion we have that

v^2 =  u^2 + 2a[s_i - s_f]

Here v is the final speed of the car

u is the initial speed of the car which is zero

s_i is the initial position of the car which is certain height H

s_i is the final position of the car which is zero meters (i.e the ground)

a is the acceleration due to gravity which is g

So

v^2 = 0 + 2g[H - 0]

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When v  = 50 \  km/h = \frac{50 *1000}{3600} = 13.9 \  m/s we have that

13.9  =  \sqrt{ 2 g H}

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