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Katen [24]
3 years ago
11

When an astronaut with a mass of 55 Kg goes from Earth to the Moon, how much does their weight change? Answer in N OR in Pounds.

gmoon= 1.62m/s2, gearth = 9.8m/s2
Physics
1 answer:
Katen [24]3 years ago
4 0

PHYSICS

mass = 55 kg

gravitation earth = 9,8 m/s²

gravitation moon = 1,62 m/s²

Weight Change = ______?

Answer :

1) Earth

w = m \times g

w = 55 × 9,8

w = 539 N

2) Moon

w \:  = m \times g

w = 55 × 1,62

w = 89.1 N

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A basketball leaves a player's hands at a height of 2.00 m above the floor. The basket is 3.05 m above the floor. The player lik
shutvik [7]

Answer:(10.69, 11.436)

Explanation:

Given

initial height of ball is 2 m

height of basket is 3.05 m

Launching angle=40^{\circ}

x =12\pm 0.27

y=1.05

equation of trajectory of ball is given by

y=xtan\theta -\frac{gx^2}{2u^2cos^2\theta }

for x=12.27

1.05=12.27\times tan40-\frac{g12.27^2}{2u^2cos^{2}40 }

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for x=11.73

1.05=11.73\times tan40-\frac{g11.73^2}{2u^2cos^{2}40 }

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Thus range of speed is (10.69, 11.436)

3 0
3 years ago
A 850-kg sports car accelerates from rest to 95 km/h in 6.8 s .
swat32

From the calculations, the power expended is 43650 W.

<h3>What is the power expended?</h3>

Now we can find the acceleration from;

v = u + at

u = 0 m/s

v =  95 km/h or 26.4 m/s

t =  6.8 s

a = ?

Now

v = at

a = v/t

a = 26.4 m/s/ 6.8 s

a = 3.88 m/s^2

Force = ma = 850-kg * 3.88 m/s^2 = 3298 N

The distance covered is obtained from;

v^2 = u^2 + 2as

v^2 = 2as

s = v^2/2a

s = (26.4)^2/2 * 3.88

s = 696.96/7.76

s = 90 m

Now;

Work = Fs

Work =  3298 N * 90 m = 296820 J

Power =  296820 J/ 6.8 s

= 43650 W

Learn more about power expended:brainly.com/question/11579192

#SPJ1

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In my opinion, calling exercise "work"  wouldn't be a good way of describing it, I don't think people would exercise if its called work 
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