Our main source of energy is the sun. True.
Answer:
2CO 2NO → 2CO2 N2 : Balanced
6CO2 6H2O → C6H12O6 : Unbalanced
H2CO3 → H2O CO2 : Balanced
2Cu O2 → CuO : Unbalanced
Explanation:
1.) 2CO 2NO → 2CO2 N2
2 Carbon 2
4 Oxygen 4
2 Nitrogen 2
The amount of atoms of each element on each side of the equation are the same therefore the equation is balanced.
2.) 6CO2 6H2O → C6H12O6 O2
6 Carbon 6
12 Oxygen 8
12 Hydrogen 12
The amount of oxygen atoms is different on both sides of the equation therefore the equation is not balanced.
3.) H2CO3 → H2O CO2
2 Hydrogen 2
1 Carbon 1
3 Oxygen 3
The amount of atoms of each element is the same on both sides of the equation therefore the equation is balanced.
2Cu O2 → CuO.
2 Cu 2
2 O 1
The amount of oxygen atoms is different on both sides of the equation therefore the equation is not balanced.
Li(s) (answer A)
Li is strongest reducing agent because of the lowest standard reduction potential. when something is oxidized, it reduces another substance, becoming a reducing.Hence Lithium is strongest reducing agent. Reducing agent is stronger when it has a more positive oxidation potential.
In formation of a Type II Binary Compound, the metal atom present is<span>
NOT</span> found in either Group 1 or Group 2 on the periodic table. For the choices, Ba is under Group 2 on the periodic table, which makes it the atom not involved in formation of type II compounds. The answer is B.
Answer:
The answer is E. All of the statements describe the anomeric carbon.
Explanation:
When a sugar switches from its open form to its ring form, the carbon from the carbonyl (aldehyde if it is an aldose, or a ketone in the case of a ketose) suffers a nucleophilic addition by one of the hydroxyls in the chain, preferably one that will form a 5 or 6 membered ring after the reaction.
As such, the anomeric carbon will have two oxygens attached (The original one and the one that bonded when the ring closed).
It will be chiral, given that it has 4 different groups attached. (-OR,-OH,-H and -R, where R is the carbon chain).
The hydroxyl group can be in any position (Above of below the ring), depending on with side the addition took place. (See attachment)
It is the carbon of the carbonyl in the open-chain form of the sugar, because it is the only one that can react with the Hydroxyls.
