Environmental Chemistry studies the health hazards associated with lead, which is dangerous to humans.
Environmental Chemistry studies chemicals present in air, water and soil and their impact on humans and their environment.
Now, it was discovered that even low doses of lead particles in the paint when inhaled or ingested caused damaging effect to the body such as Impaired balance, seizures, ataxia and even death.
With the role of Environmental chemists in thier research and findings, the world has been informed on the negative effect on the expose of lead and other heavy metals like it to man and his environment.
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Answer:
Answers are in the explanation
Explanation:
Ksp of CdF₂ is:
CdF₂(s) ⇄ Cd²⁺(aq) + 2F⁻(aq)
Ksp = 6.44x10⁻³ = [Cd²⁺] [F⁻]²
When an excess of solid is present, the solution is saturated, the molarity of Cd²⁺ is X and F⁻ 2X:
6.44x10⁻³ = [X] [2X]²
6.44x10⁻³ = 4X³
X = 0.1172M
<h3>[F⁻] = 0.2344M</h3><h3 />
Ksp of LiF is:
LiF(s) ⇄ Li⁺(aq) + F⁻(aq)
Ksp = 1.84x10⁻³ = [Li⁺] [F⁻]
When an excess of solid is present, the solution is saturated, the molarity of Li⁺ and F⁻ is XX:
1.84x10⁻³ = [X] [X]
1.84x10⁻³ = X²
X = 0.0429
<h3>[F⁻] = 0.0429M</h3><h3 /><h3>The solution of CdF₂ has the higher fluoride ion concentration</h3>
D is the answer here look
Answer:
58.0 g/mol
Explanation:
The reaction that takes place is:
- MCl₂ + 2AgNO₃ → 2AgCl + M(NO₃)₂
First we <u>calculate how many moles of silver chloride</u> were produced, using its <em>molar mass</em>:
- 6.41 g AgCl ÷ 143.32 g/mol = 0.0447 mol AgCl
Then we <u>convert AgCl moles into MCl₂ moles</u>, using the <em>stoichiometric ratio</em>:
- 0.0447 mol AgCl *
= 0.0224 mol MCl₂
Now we<u> calculate the molar mass of MCl₂</u>, using the original<em> mass of the sample</em>:
- 2.86 g / 0.0224 mol = 127.68 g/mol
We can write the molar mass of MCl₂ as:
- Molar Mass MCl₂ = Molar Mass of M + (Molar Mass of Cl)*2
- 127.68 g/mol = Molar Mass of M + (35.45 g/mol)*2
Finally we<u> calculate the molar mass</u> of M:
- Molar Mass of M = 57 g/mol
The closest option is 58.0 g/mol.
Also option C is correct. Hope it helps.
