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Gennadij [26K]
3 years ago
9

Lactic acid is produced from pyruvate by an anaerobic process called

Chemistry
2 answers:
padilas [110]3 years ago
8 0

Answer:

B. fermentation

Explanation:

this process is called lactic fermentation where a molecule of gluclose(C6H12O6) is turned into two molecules of pyruvate(C3H4O3) and the pyruvate molecules are turned into lactic acid(C3H6O3) from this process two molecules of ATP are resulted

Crank3 years ago
5 0

Answer:

Fermentation

Explanation: I took the test

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2.50g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 12
Art [367]

Answer:

                      Molecular Formula  =  C₁₀H₈

Explanation:

Step 1: <u>Calculating Moles for each Element:</u>

C  =  Mass of CO₂ × (1 mol of CO₂÷ M.Mass of CO₂) × (1 mol of C ÷ 1 mol of CO₂)

C  =  8.60 g × (1 mol of CO₂÷ 44.011 g.mol⁻¹) × (1 mol of C ÷ 1 mol of CO₂)

C =  0.1954 mol

H  =  Mass of H₂O × (1 mol of H₂O ÷ M.Mass of H₂O) × (2 mol of H ÷ 1 mol of H₂O)

H  = 1.41 g × (1 mol of H₂O ÷ 18.106 g.mol⁻¹) × (2 mol of H ÷ 1 mol of H₂O)

H =  0.1557 mol

Step 2: <u>Calculate the Smallest whole number ratio as,</u>

                                 C                                                        H

                              0.1954                                               0.1557

                      0.1954/0.1557                                  0.1557/0.1557

                               1.25                                                       1

Multiply ratio by 4,

                                 5                                                         4

Result:

          Empirical Formula of Propane is C₅H₄

Step 3: <u>Calculate Molecular Formula:</u>

Molecular formula is calculated by using following formula,

                    Molecular Formula  =  n × Empirical Formula  ---- (1)

Also, n is given as,

                     n  =  Molecular Weight / Empirical Formula Weight

Molecular Weight  =  128.0 g.mol⁻¹

Empirical Formula Weight  =  5 (C) + 4 (H) =  64 g.mol⁻¹

So,

                     n  =  128.0 g.mol⁻¹ ÷ 64 g.mol⁻¹

                     n  =  2

Putting Empirical Formula and value of "n" in equation 1,

                    Molecular Formula  = 2 × C₅H₄

                    Molecular Formula  =  C₁₀H₈

4 0
3 years ago
Compare and contrast cytokines in animal and plant cells
GarryVolchara [31]
<h3>Answer:</h3>

Cytokinesis in animal cells occur by cleavage while in plants it occurs through the formation of a cell plate.  

<h3>Explanation:</h3>
  • Cytokinesis refers to the process through which the cytoplasm divide in animal and plant cells.
  • It occurs after the division of the nucleus.
  • Cytokinesis in animal cells differs from that in plant cells in that, in animal cells it occurs by cleavage while in plant cells cytokinesis occurs through the formation of a cell plate.
  • In animal cells, cleavage occurs as a result of the activity of actin and myosin which results to dividing of cytoplasm in to two.
  • In plant cells, cell plate is formed by the fusion of golgi bodies on the equator which will generate cell wall and the plasma membrane between daughter cells.
6 0
4 years ago
Zn(s)+2HCl(aq)= Zncl2(aq)+H2(g)
algol13
<span>There are a number of ways to express concentration of a solution. This includes molarity. Molarity is expressed as the number of moles of solute per volume of the solution. We calculate as follows:
</span>
2.5 M HCl = 2.5 mol HCl / L soln

0.306 mol HCl / 2.5 mol HCl/L son = 0.1224 L soln needed

M1V1 = M2V2
18 M(V1) = 2.5 M(0.1224 L)
V1 = 0.017 L of the 18 M solution
4 0
4 years ago
Of the following reactions, which is a fission reaction?
trapecia [35]

Answer:

it's c

Explanation:

6 0
4 years ago
By titration, it is found that 28.5 mL of 0.183 M NaOH(aq) is needed to neutralize 25.0 mL of HCl(aq). Calculate the
maksim [4K]

Answer:

0.209M

Explanation:

M1V1=M2V2

(28.5 mL)(0.183M)=(25.0mL)(M)

M2= 0.209M

*Text me at 561-400-5105 for private tutoring if interested: I can do homework, labs, and other assignments :)

4 0
3 years ago
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