Answer:
54.4 mol
Explanation:
the equation for complete combustion of butane is
2C₄H₁₀ + 13O₂ ---> 8CO₂ + 10H₂O
molar ratio of butane to CO₂ is 2:8
this means that for every 2 mol of butane that reacts with excess oxygen, 8 mol of CO₂ is produced
when 2 mol of C₄H₁₀ reacts - 8 mol of CO₂ is produced
therefore when 13.6 mol of C₄H₁₀ reacts - 8/2 x 13.6 mol = 54.4 mol of CO₂ is produced
therefore 54.4 mol of CO₂ is produced
I think the answer is false
This is a characteristic of a Thermosetting polymer.
Answer:
the cycle of water and how it evaporates with energy from the sun and the droplets are stored in clouds which is condensation and when it rains or snows those are forms of precipitation
Explanation:
Explanation:
As we know that density is the amount of mass present in a liter of solution.
Mathematically, density =
As it is given that density of water is 1 g/ml and volume is 175 mL. So, mass of water will be calculated as follows.
density =
1 g/ml =
mass = 175 g
It is known that 18 g of water contains 1 mole of water. Hence, number of moles present in 175 g of water will be calculated as follows.
No. of moles =
=
= 9.72 mol
This means that we have 9.72 moles of ethanol also.
Hence, volume of ethanol present in 175 ml of water will be as follows.
No. of moles of ethanol =
9.72 mol =
Volume = 566.69 ml
Thus, we can conclude that 566.69 ml volume of ethanol contains the same number of molecules as are present in 175 ml of .