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julsineya [31]
2 years ago
14

All of the following are equivalent except x-7 X-(-7) -7+x x+(-7)

Mathematics
1 answer:
il63 [147K]2 years ago
7 0

Answer:

X-(-7)

Step-by-step explanation:

If you are subtract by a negative number it turns it into a positive. It would look like this: X+(+7)

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Find the median of these numbers 5,9,13,7,5,7
Troyanec [42]

Answer:

The mean is 7

Step-by-step explanation:

5,5,7,7,9,13

9-7 is going to get 7

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3 years ago
PLZZZ HELP!! DESPRATE!!! 15PTS!!!!!
s344n2d4d5 [400]

The correct answer is C, x is greater than -5. In order to solve this, you have to solve for x by simplifying both sides of the equation. Then you have to isolate the variable. Hope this helped!

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Find vertex of f(x)=(x+3)(x-5)
astra-53 [7]

The x coordinate of the vertex will be the average of the two zeros, here -3 and 5, so x=(-3+5)/2 = 1, f(1)=(1+3)(1-5) = -16.

Answer: (1, -16)

Let's do it some other ways.  How about completing the square to turn f in to vertex form?

f(x) = (x+3)(x-5) = x² - 2x - 15 = (x² - 2x + 1) - 1 - 15 = (x-1)² - 16

and now we can read off (1, -16) as the vertex.

The other method is the vertex is x= - b/2a =  - (-2)/2(1) = 1.

Three methods, same answer. Good.

4 0
3 years ago
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In parallelogram FGHJ if m∡ GHJ=55˚ find m∡FGH
hodyreva [135]

Answer:

∠ FGH = 125°

Step-by-step explanation:

The consecutive angles in a parallelogram are supplementary, then

∠ FGH + ∠ GHJ = 180° , that is

∠ FGH  + 55° = 180° ( subtract 55° from both sides )

∠ FGH = 125°

4 0
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A track runner is eager to see if practicing helps her improve. She has plotted data on her weekly 100-meter dash times (s) as w
insens350 [35]

Answer:

\displaystyle s = -\frac{1}{5}h + 20

Step-by-step explanation:

<em>Time</em><em> </em>is the dependent variable, so you set your function equal to <em>s</em>. Then, the correlation of the graph has a \displaystyle -\frac{1}{5}<em>rate</em><em> </em><em>of</em><em> </em><em>change</em><em> </em>[<em>slope</em>] from the y-intercept of \displaystyle [0, 20],so we choose this answer choice.

I am joyous to assist you anytime.

4 0
3 years ago
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