Answer:
<em>molar mass of the phosphorus chloride = 138.06 g/mol</em>
<em></em>
Explanation:
<em>mass of phosphorus will be the same as mass of CO2, since it is stated that they are of equal amount.</em>
mass = 3.51 g
<em>lets assume that it took the CO2 1 sec to effuse, then the time taken by the phosphorus chloride will be 1.77 sec</em>
From this we can say that
rate of effusion of CO2 = 3.51/1 = 3.51 g/s
rate of effusion of the phosphorus chloride = 3.51/1.77 = 1.98 g/s
<em>From graham's equation of effusion</em>,
= ![\sqrt{\frac{Mp\\}{Mc} }](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7BMp%5C%5C%7D%7BMc%7D%20%7D)
Rc = rate of effusion of CO2 = 3.51 g/s
Rp = rate of effusion of phosphorus chloride = 1.98 g/s
Mc = molar mass of CO2 = 44.01 g/mol
Mp = molar mass of the phosphorus chloride = ?
Imputing values into the equation, we have
= ![\sqrt{\frac{Mp\\}{44.01} }](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7BMp%5C%5C%7D%7B44.01%7D%20%7D)
1.77 = ![\frac{\sqrt{Mp} }{6.64}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7BMp%7D%20%7D%7B6.64%7D)
11.75 = ![\sqrt{Mp}](https://tex.z-dn.net/?f=%5Csqrt%7BMp%7D)
Mp = ![11.75^{2}](https://tex.z-dn.net/?f=11.75%5E%7B2%7D)
Mp = <em>molar mass of the phosphorus chloride = 138.06 g/mol</em>