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Answer: For the elementary reaction
the molecularity of the reaction is 2, and the rate law is rate = ![k[NO_3]^1[CO]^1](https://tex.z-dn.net/?f=k%5BNO_3%5D%5E1%5BCO%5D%5E1)
Explanation:
Order of the reaction is defined as the sum of the concentration of terms on which the rate of the reaction actually depends. It is the sum of the exponents of the molar concentration in the rate law expression.
Elementary reactions are defined as the reactions for which the order of the reaction is same as its molecularity and order with respect to each reactant is equal to its stoichiometric coefficient as represented in the balanced chemical reaction.
Molecularity of the reaction is defined as the number of atoms, ions or molecules that must colloid with one another simultaneously so as to result into a chemical reaction. Thus it can never be fractional.
For elementary reaction
, molecularity is 2 and rate law is ![rate=k[NO_3]^1[CO]^1](https://tex.z-dn.net/?f=rate%3Dk%5BNO_3%5D%5E1%5BCO%5D%5E1)
Each carbon atom will react with 4 hydrogen atoms to form methane (

) Since there are 2 hydrogen atoms in a hydrogen molecule (

) then each carbon atom will react with 2 hydrogen molecules. Since there are 22 hydrogen molecules half as many methane molecules will be formed, so 11. Then we can subtract 11 from 34 to find the number of carbon atoms left over.
So in summary, 11 methane molecules will be formed and there will be 23 carbon atoms left over.
Answer: Thus the value of
is 110.25
Explanation:
Initial moles of
= 0.500 mole
Initial moles of
= 0.500 mole
Volume of container = 1 L
Initial concentration of
Initial concentration of
equilibrium concentration of
[/tex]
The given balanced equilibrium reaction is,

Initial conc. 0.500 M 0.500 M 0 M
At eqm. conc. (0.500-x) M (0.500-x) M (2x) M
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[IBr]^2}{[Br_2]\times [I_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BIBr%5D%5E2%7D%7B%5BBr_2%5D%5Ctimes%20%5BI_2%5D%7D)

we are given : 2x = 0.84 M
x= 0.42
Now put all the given values in this expression, we get :


Thus the value of the equilibrium constant is 110.25