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Alexeev081 [22]
3 years ago
7

Interpret the Blame responsibility and causation in your own words in the light of Columbia Accident.

Engineering
1 answer:
Licemer1 [7]3 years ago
7 0

Answer:

Proposed Improvements and Generic Lessons

Within 2 h of losing the signal from the returning spacecraft, NASA’s Administrator established the Columbia Accident Investigation Board (CAIB) to uncover the conditions that had produced the disaster and to draw inferences that would help the US space program to emerge stronger than before (CAIB, 2003). Seven months later, the CAIB released a detailed report that included its recommendations (Starbuck and Farjoun, 2005).

The CAIB (2003) report attempted to seek answers to the following four crucial questions:

1.

Why did NASA continue to launch spacecraft despite many years of known foam debris problems?

2.

Why did NASA managers conclude, despite the concerns of their engineers, that the foam debris strike was not a threat to the safety of the mission?

3.

How could NASA have forgotten the lessons of Challenger?

4.

What should NASA do to minimize the likelihood of such accidents in the future?

Although the CAIB’s comprehensive report raised important questions and offered answers to some of them, it also left many major questions unanswered (Starbuck and Farjoun, 2005).

1.

Why did NASA consistently ignore the recommendations of several review committees that called for changes in safety organization and practices?

2.

Did managerial actions and reorganization efforts that took place after the Challenger disaster contribute, both directly and indirectly, to the Columbia disaster?

3.

Why did NASA’s leadership fail to secure more stable funding and to shield NASA’s operations from external pressures?

By examining, with respect to the Columbia disaster, the case of NASA as an organization, one can try to extract generalizations that could be useful for other organizations, especially those engaged in high-risk activities—such as nuclear power plants, oil and gas, hospitals, airlines, armies, and pharmaceutical companies—and such generic principles may also be salutary for any kind of organization.

The CAIB (2003) report recommended developing a plan to inspect the condition of all RCC systems, the investigation having found the existing inspection techniques to be inadequate. RCC panels are installed on parts of the shuttle, including the wing leading edges and nose cap, to protect against the excessive temperatures of reentry. They also recommended that taking images of each shuttle while in orbit should be standard procedure as well as upgrading the imaging system to provide three angles of view of the shuttle, from liftoff to at least SRB separation. “The existing camera sites suffer from a variety of readiness, obsolescence, and urban encroachment problems.” The board offered this suggestion because NASA had had no images of the Columbia shuttle clear enough to determine the extent of the damage to the wing. They also recommended conducting inspections of the TPS, including tiles and RCC panels, and developing action plans for repairing the system. The report included 29 recommendations, 15 of which the board specified must be completed before the shuttle returned to flight status, and also made 27 “observations” (CAIB, 2005).

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If the 1550-lb boom AB, the 190-lb cage BCD, and the 169-lb man have centers of gravity located at points G1, G2 and G3, respect
Natasha2012 [34]

Answer:

hello the required diagram is missing attached to the answer is the required diagram

7.9954 kip.ft

Explanation:

AB = 1550-Ib ( weight acting on AB )

BCD = 190 - Ib ( weight of cage )

169-Ib = weight of man inside cage

Attached is the free hand diagram of the question

calculate distance x!

= cos 75⁰ = \frac{x^!}{10ft}

    x! = 10 * cos 75^{o} = 2.59 ft

calculate distance x

= cos 75⁰ = \frac{x}{30ft}

x = 30 * cos 75⁰ = 7.765 ft

The resultant moment  produced by all the weights about point A

∑ Ma = 0

Ma = 1550 * x! + 190 ( x + 2.5 ) + 169 ( x + 2.5 + 1.75 )

Ma = 1550 * 2.59 + 190 ( 7.765 + 2.5 ) + 169 ( 7.765 + 2.5 + 1.75 )

      = 4014.5 + 1950.35 + 2030.535

      = 7995.385 ft. Ib ≈ 7.9954 kip.ft

6 0
4 years ago
Using your knowledge of how an ATM is used, develop a set of use-cases that could serve as a basis for understanding the require
drek231 [11]

Answer:

Use cases are known to be a set of instruction  or processes between a User/Actor with the system to produce a desired input.

With the aid of a diagram, the set of use cases that are carried out in this ATM are given below:

Insert PIN

(1)Perform required transaction

(2)Withdrawal

(3)Deposit

(4)Transfer

(5)Change PIN

(6)Exit

Note: Kindly find an attached diagram of the Use case as part of the solution to process carried out at the ATM

Sources: The diagram of the Use case for ATM was researched and taken from Quizlet.

Explanation:

Solution

Use cases are normally a set of instruction  or processes between a User/Actor with the system to produce a desired input.

A use case diagram or image is a graphical representation of all the use case or processes that connects or interact with the system

The use case diagram is a part of Unified Modelling Language also called the UML.

The set of use cases that are carried out in this ATM use case diagram to know the requirements of the ATM is shown below:

  • Insert PIN
  • Perform required transaction
  • Withdrawal
  • Deposit
  • Transfer
  • Change PIN
  • Exit

Now both the customer/client and Bank are seen as Actors.

Actors are the ones or people that interface with the system.

6 0
3 years ago
Sasha goes back through her architectural design books for inspiration and designs the new country club to have a Romanesque fee
vfiekz [6]
She should create a computer animated view of the design to walk the client through it so that client will understand and get the picture of the design.
3 0
3 years ago
A 35-ft³ rigid tank has propane at 25 psia, 540 R and is connected by a valve to another tank of 20 ft³ with propane at 40 psia,
gulaghasi [49]

Answer:

final pressure = 200KPa or 29.138psia

Explanation:

The detailed step by step calculations with appropriate conversion factors applied are as shown in the attachment.

8 0
4 years ago
A completely reversible heat pump produces heat ata rate of 300 kW to warm a house maintained at 24°C. Theexterior air, which is
Triss [41]

Answer:

Change in entropy S = 0.061

Second law of thermodynamics is satisfied since there is an increase in entropy

Explanation:

Heat Q = 300 kW

T2 = 24°C = 297 K

T1 = 7°C = 280 K

Change in entropy =

S = Q(1/T1 - 1/T2)

= 300(1/280 - 1/297) = 0.061

There is a positive increase in entropy so the second law is satisfied.

6 0
3 years ago
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