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2 years ago

7

Calculate the area of an applied force of 300 N and a pressure of 35 Pa? (the answer needs to be accurate with 2 decimal places!

)

1 answer:

andreyandreev [35.5K]2 years ago

4 0

Answer:

Explanation: 1Pa 1 N/m^2. p = F/A and A = F/p = 300N /35 Pa = 8.57 m^2

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Using the accepted value for the volume of 1 gram of water at the temperature of the room that you reported above, what is the accepted value for the density of water

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3 years ago

How many moles of argon are contained in 58 L of At at STP?

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Answer:

n = 2.58 mol

Explanation:

Given data:

Number of moles of argon = ?

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3 years ago

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3 years ago

Número cuántico que designa el nivel de energía en el que se localiza un electrón:

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2 years ago

What is the excess reactant in the combustion of 23 g of methane in the open atmosphere?

Marta_Voda [28]

Answer : The excess reactant in the combustion of methane in opem atmosphere is $O_{2}$ molecule.

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First we have to calculate the moles of methane.

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From the above chemical reaction, we conclude that

1 mole of methane react with the 2 moles of oxygen

and 1.434 moles of methane react to give $\frac{2moles\times 1.434moles}{1moles}$ moles of oxygen

The Moles of oxygen = 2.868 moles

Now we conclude that the moles of oxygen are more than the moles of methane.

Therefore, the excess reactant in the combustion of methane in open atmosphere is $O_{2}$ molecule.

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3 years ago