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igomit [66]
3 years ago
7

Calculate the area of an applied force of 300 N and a pressure of 35 Pa? (the answer needs to be accurate with 2 decimal places!

)​
Chemistry
1 answer:
andreyandreev [35.5K]3 years ago
4 0

Answer:

Explanation: 1Pa 1 N/m^2. p = F/A and A = F/p = 300N /35 Pa = 8.57 m^2

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What is the mass of a piece of iron if its density is 1.98 g/mL and its volume is 2.45 mL?
viktelen [127]

Answer:

4.858 g

Explanation:

Start with the formula

density = \frac{mass}{volume}

density = 1.98 g/mL

volume = 2.45 mL

mass = ??

rearrange the formula to solve for mass

(density) x (volume) = mass

Add in the substitutes and solve for mass

1.98 g/mL x 2.45 mL = 4.858 g

3 0
3 years ago
Mercury(ii) oxide (hgo) decomposes to form mercury (hg) and oxygen (o2). the balanced chemical equation is shown below. 2hgo rig
Verizon [17]

Decomposition reaction results in the formation of the products by splitting the reactants. Moles of mercury(ii) oxide needed are 15.63 moles.

<h3>What are moles?</h3>

Moles are the ratio of mass and the molar mass of the compound or the molecule.

Moles of oxygen are calculated as:

\begin{aligned}\rm n &= \rm \dfrac {mass}{molar\; mass}\\\\&= \dfrac{250}{32}\\\\&= 7.8125 \;\rm moles\end{aligned}

The balanced chemical reaction can be shown as,

\rm 2HgO \rightarrow 2Hg + O_{2}

From the reaction, it can be said that 1 mole of oxygen requires 2 moles of mercury oxide.

Moles of mercury oxide are calculated as:

\begin{aligned}  \rm n HgO& = (7.8125 \;\rm moles \; O_{2}) \times (\dfrac{2 \;\rm moles\;  HgO}{1 \;\rm mole \; O_{2}})\\\\\rm n HgO &= 15.625 \;\rm moles \end{aligned}

Therefore, option C. 15.63 moles of mercury (II) oxide is needed.

Learn more about moles here:

brainly.com/question/26898237

3 0
2 years ago
A chemistry student is given 600. mL of a clear aqueous solution at 37.° C. He is told an unknown amount of a certain compound X
barxatty [35]

Answer:

  • <u>Yes, it is 14. g of compound X in 100 ml of solution.</u>

Explanation:

The relevant fact here is:

  • the whole amount of solute disolved at 21°C is the same amount of precipitate after washing and drying the remaining liquid solution: the amount of solute before cooling the solution to 21°C is not needed, since it is soluble at 37°C but not soluble at 21°C.

That means that the precipitate that was thrown away, before evaporating the remaining liquid solution under vacuum, does not count; you must only use the amount of solute that was dissolved after cooling the solution to 21°C.

Then, the amount of solute dissolved in the 600 ml solution at 21°C is the weighed precipitate: 0.084 kg = 84 g.

With that, the solubility can be calculated from the followiing proportion:

  • 84. g solute / 600 ml solution = y / 100 ml solution

      ⇒ y = 84. g solute × 100 ml solution / 600 ml solution = 14. g.

The correct number of significant figures is 2, since the mass 0.084 kg contains two significant figures.

<u>The answer is 14. g of solute per 100 ml of solution.</u>

7 0
3 years ago
10. In what part of the world might you find Mystery Island (note: you will be given full-credit for simply attempting this ques
OLga [1]
Well countries near the quitter of warmer than countries than the poles. So the mystery island would probably be near the equator near Florida or in Florida
4 0
3 years ago
How is the word theory as it is used in science different from the common use of the word outside of science?
Neko [114]

Answer:A theory is a well-substantiated explanation of an aspect of the natural world that can incorporate laws, hypotheses and facts.

Explanation:

8 0
2 years ago
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