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ira [324]
2 years ago
13

What are scalors? give examples​

Physics
2 answers:
astra-53 [7]2 years ago
3 0

Answer:

Scalars are quantities with only magnitude, as apposed to vectors, which have magnitude and direction

Scalars include, Distance, speed, mass, temperature, time, etc.

There is only a numerical value associated with these quantities

Vectors include, Displacement, velocity, force, acceleration, etc.

There will be both a numerical value, and a direction associated with these quantities

KatRina [158]2 years ago
3 0
Scalar, a physical quantity that is completely described by its magnitude; examples of scalars are volume, density, speed, energy, mass, and time. Other quantities, such as force and velocity, have both magnitude and direction and are called vectors.
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A 4 kg mass is in free fall. What is the velocity of the mass after 11 seconds
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Velocity of the mass after 11 seconds = ( value of the gravitational acceleration) * ( time )
velocity = ( 9.81 m / s^2 ) ( 11)
velocity = 107.91 meters per second
5 0
3 years ago
. A stationary mass explodes into two parts of mass 4 kg and 40 kg . If the K.E of larger mass is 100 J . The K.E of small mass
alisha [4.7K]

Answer:

10J

Explanation:

KE = (1/2)mv²

100J = (.5)(40kg)v²

v²=(100J)/(20kg)

v²= 5

KE = 5(.5)(4kg)

KE = 10J

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2 years ago
A small glass bead has been charged to +20 nC. A small metal ball bearing 1.0 cm above the bead feels a 0.018 N downward electri
Alla [95]

Answer:

q=1\times10^{-8}C

Explanation:

Let the charge on the ball bearing is q.

charge on glass bead, Q = 20 nC = 20 x 10^-9 C

Force between them, F = 0.018 N

Distance between them, d = 1 cm = 0.01 m

By use of Coulomb's law in electrostatics

F=\frac{KQq}{d^{2}}

By substituting the values

0.018=\frac{9\times10^{9}\times20\times10^{-9}q}{0.01^{2}}

q=1\times10^{-8}C

Thus, the charge on the ball bearing is q=1\times10^{-8}C

7 0
2 years ago
What is the focus of the bandwagon advertising style?
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6 0
3 years ago
Read 2 more answers
Calculate the pressure exerted on the floor by the boy standing on both feet if the weight of the boy is 40kg. Assume that the a
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Answer:

P = 1333.33 N

Explanation:

The pressure exerted by the boy on the floor can be calculated by the following equation:

P = \frac{F}{A}

where,

P = Pressure exerted by the boy = ?

F = Force Applied = Weight of Boy = 40 kg = 40 N (since 1 kg = 1N)

A = Area of application of force = 2(Area of one show) = 2(6 cm x 25 cm)

A = 2(0.06 m x 0.25 m) = 0.03 m²

Therefore,

P = \frac{40\ N}{0.03\ m^2}\\\\

<u>P = 1333.33 N</u>

4 0
3 years ago
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