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alexandr1967 [171]
3 years ago
5

In order for radiation to transfer heat, A electromagnetic waves must be transmitted

Chemistry
1 answer:
Arlecino [84]3 years ago
6 0

Answer : A

Explanation

B- conduction

c - convection

D heat transfer

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Iron has a density of 7.86 g/cm3 (1 cm3=1 mL). Calculate the volume (in dL) of a piece of iron having a mass of 4.54 kg . Note t
lilavasa [31]
<span>The volume of iron is obtained from the density formula (density= mass/ volume) given the density and mass. In this case, 4,540 grams of iron and a density of 7.86 g/ml are given. The volume obtained from formula is 493.64 ml or 5.78 dL. </span>
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2NaHCO3--&gt;Na2CO3+H2O+CO2
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I’m not sure what kind of answer you’re looking for, but if you’re supposed to translate it into a sentence it would be two moles of sodium bicarbonate(baking soda) decompose unto one mole of sodium carbonate(soda ash) plus one mole of water and one mole of carbon monoxide gas
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How many moles are found in 10.5 g of Pb?
deff fn [24]

Answer:

Number of moles = 0.05 mol

Explanation:

Given data:

Mass of Pb = 10.5 g

Number of moles of Pb = ?

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Now we will put the values in formula.

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3 years ago
Do sound waves travel best in dense or less dense areas?
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3 0
3 years ago
Read 2 more answers
If the chemist mistakenly makes 250 mL of solution instead of the 200 mL, what molar concentration of sodium nitrate will the ch
Evgesh-ka [11]

Answer:

0.120M is the concentration of the solution

Explanation:

<em>Assuming the mass of sodium nitrate dissolved was 2.552g</em>

<em />

Molar concentration is an unit of concentration widely used in chemsitry defined as the moles of solute (In this case NaNO3) in 1L of solution.

To find this question we must find the moles of NaNO3 in 2.552g. With this mass and the volume (250mL = 0.250L) we can find molar concentration as follows:

<em>Moles NaNO3 -Molar mass: 84.99g/mol-</em>

2.552g * (1mol / 84.99g) = 0.0300 moles NaNO3

<em>Molar concentration:</em>

0.0300 moles NaNO3 / 0.250L =

<h3>0.120M is the concentration of the solution</h3>
7 0
3 years ago
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