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2 years ago

How to determine whether the object is magnetic.

Physics

2 answers:

o-na [289]2 years ago

7 0

Answer:

By holding another magnet close to it. If the object is attracted to the magnet, then it too is magnetic.

MariettaO [177]2 years ago

7 0

Based on weather or not it sticks to a magnet

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If you break a magnet in two you get

notka56 [123]

Two separate magnets.

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2 years ago

In general, how can you increase the rate of a chemical reaction?

lesantik [10]

Answer:

its 1

Explanation:

Several factors can increase the rate of a chemical reaction. In general, anything that increases the number of collisions between particles will increase the reaction rate, and anything that decreases the number of collisions between particles will decrease the chemical reaction rate.

Hope this helps? :))

3 0

2 years ago

The weather that characterizes an area is the O latitude of that area O barometric pressure of that area climate of that area O

Nikolay [14]

Answer:

climate of that area

Explanation:

3 0

2 years ago

A car travels along a straight line at a constant speed of 56.0 mi/h for a distance d and then another distance d in the same di

ioda

2* v1 * v2 / (v2+v1) = V avg2*56* v2 / (v2+56) = 33.5
v2 = 23.94 m/s

6 0

2 years ago

QUESTION 4.

n200080 [17]

Answer:

Follows are the solution to this question:

Explanation:

Please find the correct question in the attachment file.

Let:

$\overrightarrow{R}= R_i\hat{i}+R_j\hat{j}+R_k\hat{k}\\\\\overrightarrow{S}= S_i\hat{i}+S_j\hat{j}+S_k\hat{k}\\\\$

Calculating the value of $\overrightarrow{R} \times \overrightarrow{S}:$

$\to \left | \begin{array}{ccc}\hat{i}&\hat{j}&\hat{K}\\R_i&R_j&R_k\\S_i&S_j&S_k\end{array}\right | = \hat{i}[R_j S_k-S_jR_k]-\hat{j}[R_i S_k-S_iR_k]+\hat{k}[R_i S_j-S_iR_j]$

Calculating the value of $\overrightarrow{R} \cdot (\overrightarrow{R} \times \overrightarrow{S}):$

$\to (R_i\hat{i}+R_j\hat{j}+R_k\hat{k}) \cdot ( \hat{i}[R_j S_k-S_jR_k]-\hat{j}[R_i S_k-S_iR_k]+\hat{k}[R_i S_j-S_iR_j])$

by solving this value it is equal to 0.

8 0

2 years ago