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Mademuasel [1]
3 years ago
6

Help plz I ONLY GOT 2 mins left

Chemistry
2 answers:
Hoochie [10]3 years ago
5 0
I need more information... what was the experiment??
Firlakuza [10]3 years ago
3 0

Answer:

uhhh i don't know the experiment

put link and i might be able to help you

Explanation:

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What 2 materials mixed together forms a solution?
Charra [1.4K]
Lemonade mix and water

Solvent: Water
Solute: Lemonade mix
3 0
3 years ago
Read 2 more answers
Determine the molarity of 56.00 grams of aluminum nitrate in 450 milliliters of solution?
SVETLANKA909090 [29]

Answer:

4.62 M

Explanation:

Molarity = moles/volumes (L), so you need to find the moles and the volumes in liters.

Finding the volume is easy because you just have to convert mL to L, so the volume is 0.45 L

Next, find the moles. You can do this by using the molar mass of aluminum to convert the grams to moles. The molar mass of aluminum is 26.98 g/mol.

56 g * (1 mol/26.98 g) = 2.08 mol

Now, divide the moles (2.08) by the volume (.45 L)

Molarity = 4.62 M

3 0
3 years ago
If you eat 3 apples. How many apples do you have?
Ugo [173]

Answer:

Let's say we were Subtracting 3-2=? To Find the Answer we would Subtract  2 from 3 which is 1 Simple our answer is 1  But let's say the Question is 3 - 1= ? to find this answer we would subtract 1 from 3 which is 2 Let's say you were subtracting 3-3=? to do this we take 3 away from 3 now 3 is 0 so our answer is 0 so there are 3 different problems we can make with 3 we could make more but I'm just telling the basics Hope I Helped Bye :)  

Explanation:

8 0
2 years ago
Calculate δ h for the reaction:no (g) + o2 (g) ↔ no2 (g). given: 2o3(g) ↔ 3o2(g) δh=-426 kj o2(g) ↔ 2o(g) δh=+ 490 kj no(g) + o3
maks197457 [2]
To calculate the <span>δ h, we must balance first the reaction: 

NO + 0.5O2 -----> NO2

Then we write all the reactions,

2O3 -----> 3O2    </span><span>δ h = -426 kj        eq. (1)

O2 -----> 2O    </span><span>δ h = 490 kj             eq. (2)

NO + O3 -----> NO2 + O2    </span><span>δ h = -200 kj          eq. (3)


We divide eq. (1) by 2, we get

</span>O3 -----> 1.5O2    δ h = -213  kj             eq. (4)

Then, we subtract eq. (3) by eq. (4) 

NO + O3 ----->  NO2 + O2   δ h = -200 kj
-       (O3 -----> 1.5 O2         δ h = -213  kj)
NO -----> NO2 - 0.5O2        δ h = 13  kj               eq. (5)


eq. (2) divided by -2. (Note: Dividing or multiplying by negative number reverses the reaction)

O -----> 0.5O2  <span>δ h = -245  kj         eq. (6)
</span>
Add eq. (6) to eq. (5), we get

NO -----> NO2 - 0.5O2        δ h = 13  kj 
+  O -----> 0.5O2                 δ h = -245  kj
NO + O ----> NO2               δ h = -232 kj

<em>ANSWER:</em> <em>NO + O ----> NO2               δ h = -232 kj</em>


4 0
3 years ago
Explain how much risk you think your area has for water scarcity????
xz_007 [3.2K]
Not very much because half the time the water is purified but just normal water in my area probably has serious levels of scarcity.
3 0
3 years ago
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