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3 years ago

Help plz I ONLY GOT 2 mins left

Chemistry

2 answers:

Hoochie [10]3 years ago

5 0

I need more information... what was the experiment??

Firlakuza [10]3 years ago

3 0

Answer:

uhhh i don't know the experiment

put link and i might be able to help you

Explanation:

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Name this compound Cr2(CO3)3

kiruha [24]

Answer:

Molecular Weight

Explanation:

Chromium(III) Carbonate Cr2(CO3)3 Molecular Weight -- EndMemo.

5 0

3 years ago

How many milliliters of a 1.5 m h2so4 are needed to neutralize 35ml sample of a 1.5 m solution?

DochEvi [55]

Answer:

1) 17.5 mL

Explanation:

Hello,

In this case, the reaction between sulfuric acid and potassium hydroxide is:

$H_2SO_4+2KOH\rightarrow K_2SO_4+2H_2O$

In such a way, we notice a 1:2 molar ratio between the acid and the base, therefore, at the equivalence point we have:

$2*n_{acid}=n_{base}$

And in terms of concentrations and volumes:

$2*M_{acid}V_{acid}=M_{base}V_{base}$

Thus, we solve for the volume of acid:

$V_{acid}=\frac{M_{base}V_{base}}{2*M_{acid}} =\frac{35mL*1.5M}{2*1.5M} \\\\V_{acid}=17.5mL$

Best regards.

5 0

3 years ago

How many of sodium (Na) are needed to make 4.5 liters of a 1.5mol/L of Na solution?

Salsk061 [2.6K]

Answer:

Explanation:

First you will find the mole from the molarity and then the desired mass from the mole.

5 0

3 years ago

What is the isotopic symbols for <br> Beryllium atom that contains 9 nucleon?

nadya68 [22]

Answer:

Beryllium-9 is the isotope of beryllium with relative atomic mass 9.

4 0

2 years ago

Given the partial equation: NO3− Pb2 → NO2 Pb4 , balance the reaction in acidic solution using the half-reaction method and fill

Fed [463]

Answer : The balanced reaction in acidic solution is,

$2NO_3^-+1Pb^{2+}+4H^+\rightarrow 2NO_2+1Pb^{4+}+2H_2O$

Explanation :

The given partial equation is,

$NO_3^-+Pb^{2+}\rightarrow NO_2+Pb^{4+}$

First we have to separate into half reaction. The two half reactions are:

$NO_3^-\rightarrow NO_2$

$Pb^{2+}\rightarrow Pb^{4+}$

Now we have to balance the half reactions in acidic medium, we get:

$NO_3^-+2H^++1e^-\rightarrow NO_2+H_2O$ ............(1)

$Pb^{2+}\rightarrow Pb^{4+}+2e^-$ ............(2)

Now we have to balance the electrons of the half reactions. When we are multiplying the equation (1) by 2, we get

$2NO_3^-+4H^++2e^-\rightarrow 2NO_2+2H_2O$ ...........(3)

Now we have to add both the half reactions (2) and (3), we get the final balanced chemical reaction.

$2NO_3^-+1Pb^{2+}+4H^+\rightarrow 2NO_2+1Pb^{4+}+2H_2O$

3 0

3 years ago