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3 years ago

Which describes an object in projectile motion

Physics

1 answer:

alukav5142 [94]3 years ago

6 0

Answer:

Gravity acts to push the object sideways

Explanation:

projectile motion is a motion that moves along a curved path under the action of gravity only. Hope this helps!

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7. If a person starts from a standstill and the person can accelerate at 1 m/s/s, how long will it take for the person to get up

uranmaximum [27]

Use the first kinematic formula
Vf = Vi + at
10 = 0 + 1(t)
10 = t

10 seconds

6 0

3 years ago

3. Imagine a 10kg block moving with a speed of 20m/s calculate the kinetic energy of this block

MatroZZZ [7]

The formula of the kinetic energy is:
$E_{k} = \frac{m v^{2} }{2}$
where m is a mass of the object, v is speed of the object at the moment of time. So we have:
$E_{k} = \frac{10* 20^{2} }{2} = 2000J$
The answer is 2000 Joules.

6 0

3 years ago

A 90 kg man stands in a very strong wind moving at 17 m/s at torso height. As you know, he will need to lean in to the wind, and

victus00 [196]

Answer:

a) $t=195.948N.m$

b) $\phi=13.6 \textdegree$

Explanation:

From the question we are told that:

Density $\rho=1.225kg/m^2$

Velocity of wind $v=14m/s$

Dimension of rectangle:50 cm wide and 90 cm

Drag coefficient $\mu=2.05$

Generally the equation for Force is mathematically given by

$F=\frac{1}{2}\muA\rhov^2$

$F=\frac{1}{2}2.05(50*90*\frac{1}{10000})*1.225*17^2$

$F=163.29$

Therefore Torque

$t=F*r*sin\theta$

$t=163.29*1.2*sin90$

$t=195.948N.m$

Generally the equation for torque due to weight is mathematically given by

$t=d*Mg*sin90$

Where

$d=sin \phi$

Therefore

$t=sin \phi*Mg*sin90$

$195.948=833sin \phi$

$\phi=sin^{-1}\frac{195.948}{833}$

$\phi=13.6 \textdegree$

5 0

3 years ago

write a motivational speech to someone who wants to become a scientist please write this as it is for kids :) PLEASEE HELP!!!!

Gekata [30.6K]

Answer:

A motivational speech for a to be scientist. Crazy experiments and more you have the right to be whatever you adore. Your young yet strong everything will come along. I believe in you and so should you since your becoming a scientist you’ll acquire it soon. You’ll discover new things and sight to see when you become a scientist make sure to call me. :)

Explanation:

Hope it’s good I made up a couple words that rhyme good luck!

6 0

3 years ago

Read 2 more answers

If we start with 1.000 g of cobalt-60, 0.675 g will remain after 3.00 yr. this means that the of is _____

Tju [1.3M]

Cobalt-60 is undergoing a radioactivity decay.

The formula of the decay is n=N(1/2)∧(T/t).
Where N ⇒ original mass of cobalt
 n ⇒ remaining mass of cobalt after 3 years
T ⇒ decaying period
t ⇒ half-life of cobalt.

So,
0.675 = 1 × 0.5∧(3/t)
log 0.675 = log 0.5∧(3/t)
3/t = log 0.675 ÷log 0.5
3/t= 0.567

t = 3÷0.567
= 5.290626524

the half-life of Cobalt-60 is 5.29 years.

8 0

3 years ago

Which describes an object in projectile motion​

Which describes an object in projectile motion