Answer:
Using the relation V^2 = U^2 + 2× a× S
V^2 = 50^2 + (2× 5 × 240 )
V^ 2 = 2500 + 2400
V^ 2 = 4900
V= (4900)^0.5 = 70 m/s
hence, velocity at a distance of 240 m will be 70m/s.
Now using the relation,
V= U + a× t
70 = 50 + 5 × t
20 = 5 × t
t = 20/5 = 4m/s
hence , time required to travel a distance of 240m will be 4s.
Answer: d) The atomic number decreases by 2
Explanation:
A particle alpha is He(2+)
Where we have:
A = 4
Z = 2
The atomic number, the number of protons, must be conserved:
At the beginning (before the emission) we have Z protons.
After the emission, we will have an element with an atomic number X , and an alpha particle with an atomic number = 2.
Then the total number of protons after the emission is X + 2.
The conservation equation is:
Z = X + 2
Isolating X we get:
X = Z - 2
Then after the emission, the atomic number is decreased by 2.
The correct option will be:
d) The atomic number decreases by 2
Answer:
Al's mass is 102.92 kg
Explanation:
As there are no external forces in the horizontal direction, the horizontal net force must be zero:
As the force is the derivative in time of the momentum, this means that the horizontal momentum is constant:
where the suffix i and f means initial and final respectively.
The initial momentum will be:
But, as they are at rest, initially
So, this means:
We know that the have an combined mass of 195 kg:
.
so:
.
Now, we can use the values:
where the minus sign appears as they are moving at opposite directions
and this is the Al's mass.
A circuit is an unbroken loop of conductive material through which electrons flow hope this helps :)