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UkoKoshka [18]
3 years ago
6

HELP ASAP I will give you a brainliest

Chemistry
1 answer:
mixer [17]3 years ago
3 0

Answer: its the first one buster

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When alpha particles are used to bombard gold foil, most of the alpha particles pass through undeflected. this result indicates
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When alpha particles are used to bombard gold foil, most of the alpha particles pass through undeflected. This result of the experiment indicates that most of the volume of a gold atom consists of unoccupied spaces. This was an experiment done by Ernest Rutherford which allowed him to verify the presence of the a small region positive charge in an atom which is called as the nucleus of the atom. Most of the alpha particles pass through the foil while a certain amount were deflected. Those that pass through confirmed that there is a large area that is unoccupied in an atom.
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Which one of the following reactions is NOT balanced?
Korolek [52]

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co+ o2+ 2co2 is not balanced reaction

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Sheena wants to measure the volume of a ball that is 24 cm across. How should she set up her equation?
Ksivusya [100]

Answer:

The volume of a ball that is 24 cm across is :

d). v = four-thirds pi 12 cubed

Explanation :

Ball is a sphere and volume of sphere is given by :

\frac{4}{3}\Pi r^{3}

r = radius of ball

r =\frac{24}{2}

r = 12 cm

Volume is :

\frac{4}{3}\Pi \times 12^{3}

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Do foods change the pH of the body ? Explain your answer
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The alkaline diet claims to help your body maintain its blood pH level. In fact, nothing you eat is going to substantially change the pH of your blood

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At 35°C, Kc = 1.6 multiplied by10-5 for the following reaction
Brums [2.3K]

Answer : The equilibrium concentrations of all species NO,Cl_2\text{ and }NOCl are, 0.05 M, 0.043 M and 0.975 M respectively.

Explanation : Given,

Moles of  NO = 2 mole

Moles of  Cl_2 = 1 mole

Volume of solution = 1 L

Initial concentration of NO = 2 M

Initial concentration of Cl_2 = 1 M

The given balanced equilibrium reaction is,

                            2NO(g)+Cl_2(g)\rightleftharpoons 2NOCl(g)

Initial conc.          2 M            1 M            0

At eqm. conc.    (2-2x) M   (1-x) M         (2x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[NOCl]^2}{[NO]^2[Cl_2]}

The K_c for reverse reaction = \frac{1}{1.6\times 10^{-5}}

Now put all the given values in this expression, we get :

\frac{1}{1.6\times 10^{-5}}=\frac{(2x)^2}{(2-2x)^2\times (1-x)}

By solving the term 'x', we get :

x = 0.975

Thus, the concentrations of NO,Cl_2\text{ and }NOCl at equilibrium are :

Concentration of NO = (2-2x) M  = (2 - 2 × 0.975) M = 0.05 M

Concentration of Cl_2 = (1-x) M = 1 - 0.975 = 0.043 M

Concentration of NOCl = x M = 0.975 M

Therefore, the equilibrium concentrations of all species NO,Cl_2\text{ and }NOCl are, 0.05 M, 0.043 M and 0.975 M respectively.

6 0
3 years ago
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