(4) Zirconium
This element is often used in the chemical production field, and as implants due to its high chemical resistance and stability.
Answer: ![C_2H_2O_2](https://tex.z-dn.net/?f=C_2H_2O_2)
Explanation:
Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.
Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.
The empirical formula is ![CHO](https://tex.z-dn.net/?f=CHO)
The empirical weight of
= 1(12)+1(1)+1(16)= 29 g.
The molecular weight = 60 g/mole
Now we have to calculate the molecular formula:
![n=\frac{\text{Molecular weight}}{\text{Equivalent weight}}=\frac{60}{29}=2](https://tex.z-dn.net/?f=n%3D%5Cfrac%7B%5Ctext%7BMolecular%20weight%7D%7D%7B%5Ctext%7BEquivalent%20weight%7D%7D%3D%5Cfrac%7B60%7D%7B29%7D%3D2)
The molecular formula will be=![2\times CHO=C_2H_2O_2](https://tex.z-dn.net/?f=2%5Ctimes%20CHO%3DC_2H_2O_2)
Thus molecular formula will be ![C_2H_2O_2](https://tex.z-dn.net/?f=C_2H_2O_2)