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gregori [183]
3 years ago
13

First to answer gets brainliest

Physics
1 answer:
Elodia [21]3 years ago
6 0

Answer:

Sodium (K)

Explanation:

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Which is a chemical property that can be used to identify calcium carbonate?
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I think the answer is d i think
5 0
3 years ago
A box with a mass of 18 kg is pushed across the floor. It has coefficient of friction of 0.39. Calculate the force of friction i
Taya2010 [7]

Answer:

68.8 N

Explanation:

From the question given above, the following data were obtained:

Mass (m) of box = 18 Kg

Coefficient of friction (μ) = 0.39

Force of friction (F) =?

Next, we shall determine the normal force of the box. This is illustrated below:

Mass (m) of object = 18 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Normal force (N) =?

N = mg

N = 18 × 9.8

N = 176.4 N

Finally, we shall determine the force of friction experienced by the object. This is illustrated below:

Coefficient of friction (μ) = 0.39

Normal force (N) = 176.4 N

Force of friction (F) =?

F = μN

F = 0.39 × 176.4

F = 68.796 ≈ 68.8 N

Thus, the box experience a frictional force of 68.8 N.

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3 years ago
The first simple, one-celled organisms that developed during the Precambrian era are called
vovikov84 [41]
Bacteria and or archaea.
7 0
4 years ago
On earth you have a mass of 140kg in space you will have a mass of how many kg
lilavasa [31]

If your mass is 140kg , then your mass is <em>140kg</em>.  

It doesn't make a bit of difference what time it is, whether you're happy or sad, sleeping or lifting weights or running, whether it's raining or shining, hot or cold, climbing a mountain or falling out of an airplane, on the surface of a planet, asteroid, comet or star, or floating or falling through empty lonely outer space.  Your mass is your mass.  The only way it can change is if YOU make changes in yourSELF, like eating a big steak, sweating through a long tough workout, or skipping dinner, or growing to maturity.

(I guess you're already pretty mature.  If your mass is 140kg, then you weigh about 308 pounds when you're on Earth.)

 

5 0
4 years ago
Read 2 more answers
An acceptable radiograph was taken using 40 mAs at 80 kVp at a distance of 60 inches. A second radiograph is requested at 40 inc
oee [108]

Answer:

17.8 mAs

Explanation:

The exposure maintenance formula shows that as SID increases, intensity decreases, causing a decrease in film exposure and density. The mAs is directly proportional to the square of the distance. That is as mAs increases, distance increases, and vice versa, in order to maintain image receptor exposure. It is given by:

\frac{mAs_1}{mAs_2}=\frac{D_1^2}{D_2^2}

Given that mAs₁ = original mAs = 40 mAs, D₁ original distance = 60 in, D₂ = new distance = 40 in, mAs₂ = new mAs

\frac{mAs_1}{mAs_2}=\frac{D_1^2}{D_2^2}\\\\mAs_2=\frac{mAs_1*D_2^2}{D_1^2}=\frac{40*40^2}{60^2}=17.8\\\\mAs_2=17.8\ mAs

4 0
3 years ago
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