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SVETLANKA909090 [29]
3 years ago
15

An object travels a distance of 56 meters to the right in 7 seconds. What is the object's velocity?

Physics
1 answer:
Yakvenalex [24]3 years ago
8 0

Explanation:

Distance travelled (d) = 56 metres

Time taken (t) = 7 seconds

velocity of the object (V)

= d / t

= 56 / 7

= 8 m/s

The velocity of the object is 8 m/s.

Hope it will help :)

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An object is going 22 m/s and is 3 kg. find momentum
MAVERICK [17]
So what you wanna do is take your two givens. 22 and 3. Now you wanna take 22 and divide that by 3. And that gives you 7.33. Now if your answer HAS to be a whole number it'll be 66.
3 0
3 years ago
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1. A 9000 kg van was stopped at a traffic light when it rear-ended with an 850 compact car moving to the east at a velocity of 5
____ [38]

Answer:

1.785 m/s

Explanation:

The momentum can be calculated using the expression below

M1 *V1 + M2 * V2 = (M1+M2) V3

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M2= mass of car= 850kg

V3= velocity of entangled car

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V2= velocity of the car= 5 m/ s

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(900×0) + (500×5)=( 900+500)× V3

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V3=2500/1400

V3= 1.785 m/s

Hence, velocity of the entangled cars after collision is 1.785 m/s

8 0
2 years ago
A point P1 is located by the vector A = (3.74)î + (1.64)ĵ and a point P2 is located by the vector B = (1.60)î + (3.66)ĵ. The vec
seropon [69]

Answer:

\vec{C} = ( \ - 2.14 \ , \ 2.02 \ )

Explanation:

The vector that point from point P1 to point P2 its found simply by taking the vector at which point P2 its located and subtracting the vector at which point P1 its located:

\vec{C} = \vec{B} - \vec{A}

So:

\vec{C} = ( \ 1.60 \ , \ 3.66 \ ) - ( \ 3.74 \ , \ 1.64 \ )

\vec{C} = ( \ 1.60 \ - \ 3.74 \ , \ 3.66 \ - \ 1.64 \ )

\vec{C} = ( \ - 2.14 \ , \ 2.02 \ )

4 0
3 years ago
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Answer: 3 m.

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If we choose the counterclockwise direction as positive, we can write the torque equation as follows (assuming that Jill sits at the left end of the seesaw):

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