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3 years ago

Which has the largest atomic radius magnesium silicon sulfur or sodium the smallest

2 answers:

5 0

Therefore the largest atoms are on the left and the smallest on the right. So sodium (Na) has the largest atomic radius, as the valence electrons are the least attracted to the nucleus

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lianna [129]3 years ago

3 0

Answer:

Sodium (largest) and Sulfur (smallest)

Explanation:

Atomic radius of an element/atom is the distance between the central nucleus of the element/atom and the outermost shell of electrons. This indicates that the higher the number of shells, the higher the atomic radius, hence atomic radius increases down the group.

But the question focuses on elements in the same period. Magnesium (Mg), Silicon (Si), Sulfur (S) and Sodium (Na) are all found in period 3 on the periodic table. Elements having the same number of electron shells are found in the same period but the number of valence electrons plays a crucial role in atomic radius across a period - this is because the outermost shell is easily attracted to the central nucelus when there are fewer number of valence electrons on it, hence atomic radius decreases across the period as there is an increase in valence electrons across the period.

The trend below shows increasing pattern of atomic radius of the options provided

S< Si< Mg< Na

The trend shows that sulfur (S) has the smallest while sodium (Na) has the largest atomic radius.

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If two metals has the same specific heat how can distinguish them in two ways

tensa zangetsu [6.8K]

Explanation:

1) Thermal and Electric conductivity

2) Metallic strength

5 0

2 years ago

You dissolve 8.65 grams of lead(l) nitrate in water and then you add 2 50 grams of aluminum. This reaction occurs 2AI(S)+ 3Pb(NO

olga55 [171]

Answer: The theoretical yield of solid lead comes out to be 5.408 grams.

Explanation:

To calculate the moles, we use the following equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of Lead nitrate:

Given mass of lead nitrate = 8.65 grams

Molar mass of lead nitrate = 331.2 g/mol

Putting values in above equation, we get:

$\text{Number of moles}=\frac{8.65g}{331.2g/mol}=0.0261moles$

Moles of Aluminium:

Given mass of aluminium = 2.5 grams

Molar mass of aluminium = 27 g/mol

Putting values in above equation, we get:

$\text{Number of moles}=\frac{2.5g}{27g/mol}=0.0925moles$

For the given chemical reaction, the equation follows:

$2AI(s)+3Pb(NO_3)_2(aq.)\rightarrow 3Pb(s)+2AI(NO3)_3(aq.$

By Stoichiometry:

3 moles of lead nitrate reacts with 2 moles of aluminium

So, 0.0261 moles of lead nitrate are produced by = $\frac{2}{3}\times 0.0261=0.0174moles$ of aluminium.

As, the required amount of aluminium is less than the given amount. Hence, it is considered as the excess reagent.

Lead nitrate is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

3 moles of lead nitrate are produces 3 moles of lead metal.

So, 0.0261 moles of lead nitrate will produce = $\frac{3}{3}\times 0.0261=0.0261moles$ of lead metal.

Now, to calculate the grams or theoretical yield of lead metal, we put in the mole's equation, we get:

Molar mass of lead = 207.2 g/mol

Putting values in above equation, we get:

$0.0261mol=\frac{\text{Given mass}}{207.2g/mol}$

Mass of lead = 5.408 grams

Hence, the theoretical yield of solid lead comes out to be 5.408 grams.

8 0

3 years ago

Write the balanced oxidation-reduction reaction equation for the oxidation of benzoin by ammonium nitrate. 2

Margarita [4]

Benzoin is an organic compound with the formula PhCH(OH)C(O)Ph. It is a hydroxy ketone attached to two phenyl groups.

To answer your question, the balanced oxidation-reduction reaction equation for the oxidation of benzoin by ammonium nitrate is:

2Ph-C(OH)-C(O)-Ph+NH4NO3 --> 2Ph-C(O)-C(O)-Ph + N2 + 3H2O.

I hope this helps and if you have any further questions, please don’t hesitate to ask again.

7 0

2 years ago

What is the difference between solute and solvent

ratelena [41]

Answer:

A solvent is a substance which dissolves a solute. When a solvent dissolves into a solute, it creates a solution

5 0

3 years ago

18-19. If a sample for spectrophotometric analysis is placed in a 10-cm cell, the absorbance will be 10 times greater than the a

miss Akunina [59]

Answer:

As long as it is a blank solution of the reagent, the Absorbance will be 0 regardless of the path length.

Explanation:

Absorbance of light by a reagent of concentration c, is given as

A = εcl

A = Absorbance

ε = molar absorptivity

c = concentration of reagent.

l = length of light path or length of the solution the light passes through.

So, if all.other factors are held constant, If a sample for spectrophotometric analysis is placed in a 10-cm cell, the absorbance will be 10 times greater than the absorbance in a 1-cm cell.

But the reagent blank solution is called a blank solution because it lacks the given reagent. A blank solution does not contain detectable amounts of the reagent under consideration. That is, the concentration of reagent in the blank solution is 0.

Hence, the Absorbance is subsequently 0. And increasing or decreasing the path length of light will not change anything. As long as it is a blank solution of the reagent, the Absorbance will be 0 regardless of the path length.

Hope this Helps!!!

5 0

3 years ago