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Leno4ka [110]
3 years ago
9

A grocery store sells 5-lb bags of mangoes. You purchase four bags over the course

Physics
1 answer:
sergij07 [2.7K]3 years ago
3 0

Answer:

Accurate

Explanation:

Accuracy deals with the nearness of the measured values to the true value.

Precision is the ability to reproduce a certain result in a repeated fashion.

  • From the given masses of the 5-lb bags, we see that the mean value of the measurement is 5.1-lb
  • This value is very close to the original mass of the bag which is 5-lb bags.
  • We can say the reading is accurate

The reading is not precise because, the same weight is not reproduced. Different values of weight was reported from each of the measurement process.

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Hooke's law describes an ideal spring. Many real springs are better described by the restoring force (F Sp ) s =−kΔs−q(Δs) 3 (p)
Montano1993 [528]

Answer with Explanation:

We are given that

Restoring force,(FS_p)s=-k\Delta s-q(\Delta s)^3

k=350N/m

q=750 N/m^3

We have to find the work must you do to compress this spring 15 cm.

\Delta s=15 cm=0.15 m

Using 1 m=100 cm

Work done=\int_{0}^{0.15}-Fd(\Delta s)

W=-\int_{0}^{0.15}(-k\Delta s-q(\Delta s)^3))d(\Delta s)

W=k[\frac{(\Delta s)^2}{2}]^{0.15}_{0}+q[\frac{(\Delta s)^4}{4}]^{0.15}_{0}

W=0.01125k+0.000127q=0.01125\times 350+0.000127\times 750

W=4.033 J

Ideal spring work=0.5k(\Delta s)^2=0.5\times 350\times (0.15)^2=3.938 J

Percentage increase in work=\frac{4.033-3.938}{3.928}\times 100=2.4%

6 0
4 years ago
A projectile was launched horizontally with a velocity of 388 m/s, 2.89 m above the ground. How long did it take the projectile
tamaranim1 [39]

Answer:

Explanation:

Given

Velocity = 388m/s

Height S = 2.89m

Required

Time

Using the equation of motion

S =ut+1/2gt²

2.89 = 388t+1/2(9.8)t²

2.89 = 388t+4.9t²

Rearrange

4.9t²+388t-2.89 =0

Factorize

t = -388±√388²-4(4.9)(2.89)/2(4.9)

t= -388±√(388²-56.644)/9.8

t = -388±387.93/9.8

t =0.073/9.8

t = 0.00744 seconds

6 0
3 years ago
Calculate the amount of work done if you use a 100N force to push a 50kg box 5m across the kitchen floor.
irinina [24]
So if the formula for work is force times displacement times cosine(theta), you'd plug in the numbers

100x5 (since there's no angle in the problem, cosine(theta) isn't used

100x5 = 500

So the answer would be B.

Hope that helps!
6 0
3 years ago
Read 2 more answers
The largest number of stable nuclei have an ________ number of protons and an ________ number of neutrons.
xxMikexx [17]

Answer:

83 protons   126 neutrons. Bismuth Atom

Explanation:

The largest number of stable nuclei which could ever exist is the bismuth atom. A nuclei which is higher than that 83 protons is unstable and the nucleus will eventually breakdown through radioactivity.

4 0
3 years ago
Two ice skaters, Daniel (mass 70.0 kg) and Rebecca (mass 45.0 kg), are practicing. Daniel stops to tie his shoelace and, while a
Ivan

Answer:

The magnitude of  Daniel's velocity after collision is 6.84 m/s.

Explanation:

Given that,

Mass of Daniel = 70.0 Kg

Mass of Rebecca = 45.0 kg

Initial speed of Rebecca= 13.0 m/s

Final speed of Rebecca = 6.00 m/s

Angle = 54.1°

Suppose we need to calculate the magnitude of Daniel's velocity after the collision

We need to calculate the velocity of Daniel along x axis

Using conservation of momentum

m_{d}u_{d}+m_{r}u_{r}=m_{d}v_{d}+m_{r}v_{r}\cos\theta

Put the value into the formula

0+45\times13.0=70\times v_{x}+45\times6\cos54.1

v_{x}=\dfrac{45\times13-45\times6\cos54.1}{70}

v_{x}=6.09\ m/s

We need to calculate the velocity of Daniel along y axis

Using conservation of momentum

m_{d}u_{d}+m_{r}u_{r}\sin\theta=m_{d}v_{d}+m_{r}v_{r}

Put the value into the formula

0+45\times6.00\sin54.1=70\times v_{y}+0

v_{y}=\dfrac{45\times6.00\sin54.1}{70}

v_{y}=3.12\ m/s

We need to calculate the magnitude of velocity after collision

Using formula of velocity

v=\sqrt{v_{x}^2+v_{y}^2}

Put the value into the formula

v=\sqrt{(6.09)^2+(3.12)^2}

v=6.84\ m/s

Hence, The magnitude of  Daniel's velocity after collision is 6.84 m/s.

3 0
3 years ago
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