Answer:
<em>The speed of the block = 3.20 m/s</em>
Explanation:
Speed: <em>This is defined as the rate of change of distance. The S.I unit of speed is m/s.</em>
Force = Mass × Acceleration
F = ma
making a the subject of the equation,
a = F/m........................ Equation 1
<em>Given: F= 12.1 N, m = 7.06 kg.</em>
<em>Substituting these values into equation 1</em>
<em>a = 12.1/7.06</em>
<em>a = 1.71 m/s²</em>
<em>Using Newton's equation of motion, </em>
<em>v² = u² + 2as................. Equation 2</em>
<em>Where v = final velocity, u = initial velocity, a = acceleration, s = distance.</em>
Given: u = 0 (the block was initially at rest), a =1.71 m/s², s = 3 m
Substituting these values into equation 2,
v² = 0² + 2(1.71)(3)
v² = 10.26
√v² = √10.26
v = 3.20 m/s
<em>Therefor the speed of the block = 3.20 m/s</em>