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4 years ago

How can recycling impact the environment?

Physics

1 answer:

Diano4ka-milaya [45]4 years ago

6 0

Answer:

a is a good answer

Explanation:

because most items whether clothes or things we eat with, are made with something natural and recycled

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What type of object is called the object in motion?

Lynna [10]

Answer: An object is in motion when its distance from another object is changing . A reference point is a place or object used for comparison to determine if something is in motion. An object is in motion if it changes position relative to a reference point. You assume that the reference point is stationary, or not moving

Explanation:

4 0

3 years ago

Suppose you are running late in the morning and drying your hair in the kitchen with the hairdryer plugged into the outlet with

lesantik [10]

Answer:

Explanation:

It is given that Hair dryer , Toaster and coffeepot are working simultaneously with power 1200 W , 700 W and 800 W respectively.

So the total power of system is $P_t=1200+700+800=2700\ W$

it is given that they work properly until toast is on.

By switching on the toast, appliance stop working because it may cause the circuit to break to safeguard the circuit.

Circuit breaker frame are used in home to prevent the short circuit

7 0

4 years ago

A plane fillies along a straight line path after taking off and it ends up 220 km farther east and 110km farther north relative

DENIUS [597]

330km hope this helped you.

3 0

3 years ago

A man starts his car from rest and accelerates at 1 m/s2 for 2 s. He then continues at a constant velocity for 10 s until

Bumek [7]

Answer: I showed you all calculation . You did not attach any graph to question .

Explanation:

Lets first find Velocity

Vr=o m/s

Ve=?

a=1m/s²

t=2s

----------

a=(Vr-V)/t

1m/s²=Vr-0m/s/2s

2m/s=Vr

Lets find the time neeeded to stop :

a=1m/s²

Vs=2m/s

Vf=0m/s

a=(Vf-Vs)/t

t*1m/s²=2m/s

t=2 s

4 0

3 years ago

Read 2 more answers

12*3a car is stopped at a traffic light. it then travels along a straight road so that its distance from the light is given by w

Digiron [165]

Missing parts in the text of the exercise:
- The distance from the traffic light is given by $x(t) = bt^2 -ct^3$ , where $b=2.4 m/s^2$ and $c=0.13 m/s^3$

Solution:

part a) calculate the average velocity of the car for the time interval t=0 to t=8.0 s
- The average velocity is given by the ratio between the distance covered in the time interval:
 $v_{ave} = \frac{x(8.0 s)-x(0 s)}{8.0 s-0 s}$
x(0 s), the distance covered after t=0 s, is zero, while the distance after t=8.0 s is
$x(8.0 s)=b(8 s)^2-c(8 s)^3 = (2.4 m/s^2)(8 s)^2 -(0.13 m/s^3)(8 s)^3=$
$=87.04 m$
Therefore, the average velocity is
$v_{ave}= \frac{x(8.0 s)-x(0)}{8.0s-0}= \frac{87.04 m}{8.0s}= 10.88 m/s$

part b) calculate the instantaneous velocity of the car at t=0, t=4.0 s and t=8.0 s
- The instantaneous velocity can be found by performing the derivation of x(t):
 $v(t) = \frac{dx(t)}{dt}=2bt-3ct^2$
So now we just have to substitute t=0, t=4 s and t=8 s:
- t=0: v(0)=0
- t=4 s: $v(4.0 s)=2(2.4 m/s^2)(4.0 s)-3(0.13 m/s^2)(4.0s)^2=12.96 m/s$
- t=8 s: $v(8.0 s)=2(2.4 m/s^2)(8.0 s)-3(0.13 m/s^2)(8.0s)^2=13.44 m/s$

part c) how long after starting from rest is the car again at rest?
- To solve this part we must find the value of t for which v(t)=0, so:
 $2bt-3ct^2=0$
$t(2b-3ct)=0$
The first solution is t=0 s, which corresponds to the beginning of the motion, so we are not interested in this value. The second solution is
 $t= \frac{2b}{3c}= \frac{2\cdot 2.4 m/s^2}{3 \cdot 0.13 m/s^3}=12.31 s$
and this is the time at which the car is at rest again.

8 0

3 years ago