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SashulF [63]
3 years ago
8

A worker with spikes on his shoes applies a constant horizontal force of 20 N to push a 40-kg box across a frictionless, frozen

lake. What is the acceleration of the box?
2.0 m/s^2
0.5 m/s^2
4.1 m/s^2
8.0 m/s^2
Physics
2 answers:
Marina86 [1]3 years ago
5 0

Answer:

0.5m/s2

Explanation:

because since newtons third law states that f=ma

hence force is 20N and m=40kg

hence by substituting in formula we get a=0.5m/s2

Kruka [31]3 years ago
5 0

The acceleration of the box will be{\bold0.5 m/s^2.}

Explanation:

Given:

Constant horizontal force on the box= 20 N

Mass of the box=40kg

To Find:

Acceleration of the box=?

Solution:

According to Newton's Second  Law,

Force = Mass x Acceleration

On substituting the values,

20 = 40 \times Acceleration

Solving the equation for Acceleration

20 = 40 \times Acceleration

Acceleration= \frac{1}{2}

Acceleration = 0.5 m/s^2

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1) 0.0011 rad/s

2) 7667 m/s

Explanation:

1)

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where

\theta is the angular displacement of the object

t is the time elapsed

\omega is the angular velocity

In this problem, the Hubble telescope completes an entire orbit in 95 minutes. The angle covered in one entire orbit is

\theta=2\pi rad

And the time taken is

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Therefore, the angular velocity of the telescope is

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2)

For an object in circular motion, the relationship between angular velocity and linear velocity is given by the equation

v=\omega r

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v is the linear velocity

\omega is the angular velocity

r is the radius of the circular orbit

In this problem:

\omega=0.0011 rad/s is the angular velocity of the Hubble telescope

The telescope is at an altitude of

h = 600 km

over the Earth's surface, which has a radius of

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So the actual radius of the Hubble's orbit is

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Therefore, the linear velocity of the telescope is:

v=\omega r=(0.0011)(6.97\cdot 10^6)=7667 m/s

4 0
3 years ago
A pitcher is in 85° of abduction, holding a 1.4 N baseball at point C, 65 cm from the joint axis at point O • The center of grav
erastovalidia [21]

I attached a Diagram for this problem.

We star considering the system is in equlibrium, so

Fm makes 90-(\theta+5) with vertical

Fm makes 70 with vertical

Applying summatory in X we have,

\sum F_x = 0

W+1.4-Fm cos(70)

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Fm cos (70) = 6N + 1.4N

Fm = \frac{7.4}{cos(70)}

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3 0
3 years ago
A rifle is fired and recoils when the bullet leaves the gun. This is an example of Newton's third law. The acceleration of the b
sweet [91]
<span>The acceleration of the bullet is called ACTION.

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I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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During the internal examination, the pathologist drains the intestines, removes any undigested food and feces,and examines the c
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During the internal examination, the pathologist drains the intestines, removes any undigested food and feces, and examines the contents of the stomach. This examination could give the pathologist clues of the time of death, and the location of death.  The process of digesting and defecation vary from person to person, the entire process is generally considered to take approximately 40 hours in adults
8 0
3 years ago
The speed of a moving bullet can be deter-
Bad White [126]

Answer:

<em>v = 381 m/s</em>

Explanation:

<u>Linear Speed</u>

The linear speed of the bullet is calculated by the formula:

\displaystyle v=\frac{x}{t}

Where:

x = Distance traveled

t = Time needed to travel x

We are given the distance the bullet travels x=61 cm = 0.61 m. We need to determine the time the bullet took to make the holes between the two disks.

The formula for the angular speed of a rotating object is:

\displaystyle \omega=\frac{\theta}{t}

Where θ is the angular displacement and t is the time. Solving for t:

\displaystyle t=\frac{\theta}{\omega}

The angular displacement is θ=14°. Converting to radians:

\theta=14*\pi/180=0.2443\ rad

The angular speed is w=1436 rev/min. Converting to rad/s:

\omega = 1436*2\pi/60=150.3776\ rad/s

Thus the time is:

\displaystyle t=\frac{0.2443\ rad}{150.3776\ rad/s}

t = 0.0016 s

Thus the speed of the bullet is:

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v = 381 m/s

7 0
3 years ago
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