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SashulF [63]
4 years ago
8

A worker with spikes on his shoes applies a constant horizontal force of 20 N to push a 40-kg box across a frictionless, frozen

lake. What is the acceleration of the box?
2.0 m/s^2
0.5 m/s^2
4.1 m/s^2
8.0 m/s^2
Physics
2 answers:
Marina86 [1]4 years ago
5 0

Answer:

0.5m/s2

Explanation:

because since newtons third law states that f=ma

hence force is 20N and m=40kg

hence by substituting in formula we get a=0.5m/s2

Kruka [31]4 years ago
5 0

The acceleration of the box will be{\bold0.5 m/s^2.}

Explanation:

Given:

Constant horizontal force on the box= 20 N

Mass of the box=40kg

To Find:

Acceleration of the box=?

Solution:

According to Newton's Second  Law,

Force = Mass x Acceleration

On substituting the values,

20 = 40 \times Acceleration

Solving the equation for Acceleration

20 = 40 \times Acceleration

Acceleration= \frac{1}{2}

Acceleration = 0.5 m/s^2

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When the frequency of an electromagnetic wave increases, its energy
OverLord2011 [107]
The energy stays the same
8 0
3 years ago
Read 2 more answers
A wire 95.0 mm long is bent in a right angle such that the wire starts at the origin and goes in a straight line to x = 40.0 mm
qaws [65]

Answer:

0.1040512455 N

36.03^{\circ}\ or\ 323.97^{\circ}in\ CCW\ direction

0.05925 N

29.74^{\circ}\ or\ 330.26^{\circ}in\ CCW\ direction

Explanation:

I = Current

B = Magnetic field

Separation between end points is

l=\sqrt{40^2+55^2}\\\Rightarrow l=68.00735\ mm

Effective force is given by

F=IlB\\\Rightarrow F=5.1\times 68.00735\times 10^{-3}\times 0.3\\\Rightarrow F=0.1040512455\ N

The force is 0.1040512455 N

tan\theta=\dfrac{55}{40}\\\Rightarrow \theta=tan^{-1}\dfrac{55}{40}\\\Rightarrow \theta=53.97^{\circ}

The angle the force makes is given by

\alpha=\theta-90\\\Rightarrow \alpha=53.97-90\\\Rightarrow \alpha=-36.03^{\circ}\ or\ 323.97^{\circ}in\ CCW\ direction

The direction is 36.03^{\circ}\ or\ 323.97^{\circ}in\ CCW\ direction

F=IlB\\\Rightarrow F=4.9\times \sqrt{20^2+35^2}\times 10^{-3}\times 0.3\\\Rightarrow F=0.05925\ N

The force is 0.05925 N

tan\theta=\dfrac{35}{20}\\\Rightarrow \theta=tan^{-1}\dfrac{35}{20}\\\Rightarrow \theta=60.26^{\circ}

\alpha=\theta-90\\\Rightarrow \alpha=60.26-90\\\Rightarrow \alpha=-29.74^{\circ}\ or\ 330.26^{\circ}in\ CCW\ direction

The direction is 29.74^{\circ}\ or\ 330.26^{\circ}in\ CCW\ direction

4 0
3 years ago
if 162.4 j of heat are added to a gas contained within a cylinder and the gas expands, doing 87.3 j of work, what is the change
labwork [276]

The changes in internal energy of the system <u>75.1 J.</u>

The internal energy of a thermodynamic system is the total energy contained in it. It is the energy required to create or prepare a system in a given internal state and includes contributions of potential energy and internal kinetic energy.

Calculation:

Internal energy =  162.4 j - work done

                        =  162.4 j - 87.3 j

                         =<u> 75.1 J</u>

<u />

Internal energy, in thermodynamics, is the property or state function that defines the energy of matter in the absence of capillary action or external electric, magnetic, or other fields.

Internal energy is the microscopic energy contained in the matter given by the random and disordered kinetic energy of the molecules. It also includes the potential energy between these molecules and the nuclear energy contained in the atoms of these molecules.

Learn more about internal energy here:-brainly.com/question/15735187

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6 0
1 year ago
Simplified. The absorption spectra of ions have been used to identify the presence of the elements in the atmospheres of the sun
Nookie1986 [14]

Answer:

The answer is "3.83 \times 10^9 \ m"

Explanation:

Z=2, so the equation is E= \frac{-4B}{n^2}

Calculate the value for E when:  

n=2 and n=9

The energy is the difference in transformation, name the energy delta E Deduct these two energies  

In this transition, the wavelength of the photon emitted is:

\Delta E=2.18 \times  10^{-18} ( \frac{1}{4}- \frac{1}{81})

\lambda = \frac{h c}{\Delta E}

h ( Planck's\  constant) = 6.62 \times  10^{(-34)} \ Js \\\\ speed \ of \ light = 3 \times 10^{8} \ \frac{m}{s}\\\\= \frac{6.62 \times 10^{(-34)} \times 3 \times 10^ {8}}{2.18 \times  10^{-18}} (\frac{1}{4}- \frac{1}{81}) \\\\=3.83 \times 10^9 \ m\\\\

6 0
3 years ago
What is the velocity of a fly with a mass of approximately 6.85 times 10 to the negative 6 slugs if it has a kinetic energy of 5
vodka [1.7K]

Velocity of the fly: 1318 m/s

Explanation:

The kinetic energy of an object is the energy possessed by the object due to its motion. It can be calculated as

K=\frac{1}{2}mv^2

where

m is the mass of the object

v is its speed

For the fly in this problem, we have

m=6.85\cdot 10^{-6} kg is the mass

K = 5.95 J is the kinetic energy

Solving for v, we find its velocity:

v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(5.95)}{(6.85\cdot 10^{-6})}}=1318 m/s

Learn more about kinetic energy:

brainly.com/question/6536722

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4 0
3 years ago
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