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dexar [7]
2 years ago
8

PLEASE HELP

Chemistry
1 answer:
Snezhnost [94]2 years ago
7 0
Use Calcium Chloride.  sucrose doesn't break apart so it won't decrease the freezing point much, NaCl is better because you have twice as many ions running around than sucrose, and CaCl2 is the best because it has 3 ions dissolved instead of 1 or 2 like the others.
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The density of gold is 19.3 g /cm cubed The density of iron pyrite is 5.0 g /cm cubed. Is a nugget of iron pyrite and a nugget o
telo118 [61]
If you clear volume in the density equation:

\rho = \frac{m}{V}\ \to\ V = \frac{m}{\rho}

The greater the density the lower the volume. This means, the volume of gold nugget will be smaller than the volume of iron pyrite nugget.

V_{gold} = \frac{m}{\rho} = \frac{50\ g}{19.3\ g/cm^3} = \bf 2.59\ cm^3

V_{iron} = \frac{m}{\rho} = \frac{50\ g}{5.0\ g/cm^3} = \bf 10\ cm^3
6 0
3 years ago
Which two phase changes occur when you increase the heat?
muminat

Answer:

Heat going into a substance changes it from a solid to a liquid or a liquid to a gas. Removing heat from a substance changes a gas to a liquid or a liquid to a solid.

Liquid → Gas: 

VaporizationGas → Liquid:

 CondensationSolid → Liquid:

 Melting or fusion

Solid → Gas: Sublimation

Explanation:

8 0
1 year ago
How could measuring the melting point of a solid help decide whether it was a mixture or a compound?
mars1129 [50]

Answer: It can't.

Explanation:

In most cases, the melting point alone will not enable you to identify a compound. Millions of solid organic compounds, and their melting points, are known. Perhaps 10,000 of these will have the same melting point as your unknown compound.

Hope this helps!

8 0
2 years ago
98 POINTS! MUST SHOW YOUR WORK for Brainliest!
Annette [7]

1 mole has 6.02*10^23 molecules in it.

1 nickel (II) chloride molecule, NiCl2, has 1 Ni atom in it.

so 1 mole of nickel (II) chloride molecule has 1 mole of Ni atom in it.

so 100 moles of nickel (II) chloride molecule has 100*6.02*10^23

= 6.02*10^25 Ni atom in it.


5 0
3 years ago
Read 2 more answers
A sample of rubidium contains two different isotopes. 72.15% of the sample
Leona [35]

Answer:

Average atomic mass  = 85.557 amu.

Explanation:

Given data:

Percent abundance of Rb-85 = 72.15%

Percent abundance of Rb-87 = 27.85%

Average atomic mass = ?

Solution:

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass = (72.15×85)+(27.85×87) /100

Average atomic mass =  6132.75 + 2422.95 / 100

Average atomic mass = 8555.7 / 100

Average atomic mass  = 85.557 amu.

4 0
2 years ago
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