C. Decreasing the temperature
D. Raising the pressure
<h3>Further explanation</h3>
Given
Reaction
2SO₂+O₂⇔2SO₃+energy
Required
Changes to the formation of products
Solution
The formation of SO₃ is an exothermic reaction (releases heat)
If the system temperature is raised, then the equilibrium reaction will reduce the temperature by shifting the reaction in the direction that requires heat (endotherms). Conversely, if the temperature is lowered, then the equilibrium shifts to a reaction that releases heat (exothermic)
While on the change in pressure, then the addition of pressure, the reaction will shift towards a smaller reaction coefficient
in the above reaction: the number of coefficients on the left is 3 (2 + 1) while the right is 2
As the temperature decreases, the equilibrium will shift towards the exothermic reaction, so the reaction shifts to the right towards SO₃( products-favored)
And increasing the pressure, then the reaction shifts to the right SO₃( products-favored)⇒the number of coefficients is greater
They do this in order to survive their new environment. If they didn't adapt, then they would die!
There would be an equal amounts of ELECTRONS.
In order for the atom to be neutral it would imply that the number of protons (positive particles) and the number of electrons (negative particles) are equal since the neutrons are without charge.
a) CH2O
each element can be divided by 2
b) BCl3
the molecule is already in it's empirical formula
c) CH4
the molecule is already in it's empirical formula
d)CH2O
each element can be divided by 6
Tin and Hydrofluoric Acid reacts as shown,
<span> Sn + 2 HF </span>→ SnF₂<span> + H</span>₂
According to Equation,
40.02 g (2 Moles) HF Required = <span>1 Mole of Sn for complete Reaction
So,
40 g of HF will require = X Moles of Sn
Solving for X,
X = (40 g </span>× 1 Mole) ÷ 40.02 g
X = 0.999 Moles ≈ 1 Mole
Result:
40 g of HF requires 1 Mole of Tin (Sn) for complete Reaction to produce SnF₂ and H₂.
