He will swim 180m if he stays at a constant rate of 30m/min
Explanation:
First I’m going to use 6 min for the 5min 60s
Then if he swims 30m/min then I’m 6min, 30•6 he’ll swim 180m
Hope this helps!
The value of the equivalent resistance for the three resistors connected in series will be the sum of the three values.
To find the answer, we have to know more about the equivalent resistance.
<h3>
What is meant by equivalent resistance?</h3>
- equivalent resistance is the total value of the resistance connected in a circuit.
- If n resistors are connected in series, then the equivalent resistance will be,
- In our question we have three resistors. Thus, the equivalent resistance will be,
Thus, we can conclude that, the value of the equivalent resistance for the three resistors connected in series will be the sum of the three values.
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P.E = m*g*d
where m is the mass of body , d the vertical distance & g is the gravity acceleration and it equals constant = 9.81 m/s^2
so ,, P.E = 2 * 3 * 9.81
P.E = 58.86 N.m
The lower the value of the coefficient of friction, the lower the resistance to sliding.
<u>Explanation:</u>
The coefficient of friction defines as directly proportionate with the resisting force, which is the frictional force. Hence, if there seems a decrease at coefficient of friction, then it is sure that the frictional force decreases.
We know that the frictional force on a body, is the product of coefficient of frictions and the normal forces acting on the body. Note that friction acts only, if a body is in contact, and it is of three types, static, kinetic and rolling.
The lowest constant acceleration needed for takeoff from a 1.80 km runway is 2.8 m/s².
To find the answer, we need to know about the Newton's equation of motion.
<h3>What's the Newton's equation of motion to find the acceleration in term of initial velocity, final velocity and distance?</h3>
- The Newton's equation of motion that connects velocity, distance and acceleration is V² - U²= 2aS
- V= final velocity, U= initial velocity, S= distance and a= acceleration
<h3>What's the acceleration, if the initial velocity, final velocity and distance are 0 m/s, 360km/h and 1.8 km respectively?</h3>
- Here, S= 1.8 km or 1800 m, V= 360km/h or 100m/s , U= 0 m/s
- So, 100²-0= 2×a×1800
=> 10000= 3600a
=> a= 10000/3600 = 2.8 m/s²
Thus, we can conclude that the lowest constant acceleration needed for takeoff from a 1.80 km runway is 2.8 m/s².
Learn more about the Newton's equation of motion here:
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