Match each planet to an accurate characteristic

What is the main determining factor in defining boundaries between layers of earth's atmosphere?

konstantin123 [22]

The main determining factor in defining boundaries between layers of earth's atmosphere would be temperature changes in these layers. Temperature is one essential property that varies in the atmosphere. Based from this variation, the atmosphere is divided into four major layers and further to three smaller layers - troposphere, tropopause, the stratosphere, stratopause, the mesosphere, mesopause, and the thermosphere.The troposphere is the layer that is nearest to the surface of the Earth. It is the part where humans, plants and animals survive. Also, it is the warmest layer of the atmosphere. And as we go higher the atmosphere, the temperature would drop making it much cooler.

5 0

3 years ago

Read 2 more answers

Explain Newtons Laws

Vsevolod [243]

1) Newton first law of motion: state“If a body is at rest it reamain at rest and if it is in a motion it continu its motion unless a net external force acting on it”

This law also called law of inertia

2) Newton second law of motion: states that ‟acceleration to the force acting on the body and inversky proportional to the mass of the body”

3) Newton's third law of motion: It is not possible to exert a force abody with out the body exerting a forces in the opposite direction.

These forces are called action and reaction forces

hope it's helpful ❤❤❤❤❤❤

THANK YOU.

8 0

3 years ago

a) If a proton moved from a location with a 5.0 V potential to a location with 7.5 V potential, would its potential energy incre

tekilochka [14]

Answer:

A. The potential energy of the positively charge proton from 5v to 7.5v will increase because in an electric field work is done on the proton to move it to a point of higher potential

B. when an electron is moved from 7.5v to 5v it loses potential energy due to the charges lost so as to bring it to a point of lower potential

Explanation:

3 0

3 years ago

An incline plane has Ф = 40.0° and μ k = 0.15. Starting from rest, how long will it take a 4.0 kg block to reach a speed of 12 m

lesya [120]

The block on the action of two forces, the Force of Friction and the Tangential Weight. Using the Newton's Secound Law, we have:

$P_{t}-Fat=ma \\ mgsen\O-mgucos\O=ma \\ a=g(sen\O-ucos\O)$

Using the Velocity Hourly Equation, we get:

$V=V_{o}+a\Delta t \\ \Delta t= \frac{V}{a}$

Uniting the equations:

$\Delta t= \frac{V}{g(sen\O-ucos\O)}$

Entering the unknowns:

$\Delta t= \frac{V}{g(sen\O-ucos\O)} \\ \Delta t= \frac{12}{10(sen40^o-0.15cos^o)} \\ \Delta t= \frac{12}{10(0,64-0.15x0.77)} \\ \Delta t= \frac{12}{5.27} \\ \boxed {\Delta t=2.28s}$

Obs: Approximate results

If you notice any mistake in my english, please let me know, because i am not native.

5 0

3 years ago

Why is a flower not a good blackbody radiator?

Alecsey [184]

Answer:

A flower emits only visible light

A flower reflects much of the light that hits it

8 0

3 years ago