Ask question

Ask question

All categories

3 years ago

14

How is energy that is stored in food released?

2 answers:

kumpel [21]3 years ago

7 0

Answer:

i think its A

Explanation:

Triss [41]3 years ago

3 0

Answer:

D

Explanation:

The chemical energy stored in food is released by cells through the process of respiration. (cellular respiration)

This stored energy is released whenever these chemical bonds are broken in metabolic processes such as cellular respiration. Cellular respiration is the process by which the chemical energy of “food” molecules is released and partially captured in the form of ATP.

You might be interested in

Dos cargas iguales de 10^-7C estan separadas por una distancia de 2m. calcule la fuerza con que se repelen

m_a_m_a [10]

Answer:

$F=2.25\times 10^{-5}\ N$

Explanation:

According to question,

Charge 1 and charge 2 are $10^{-7}\ C$

The distance between charges is 2 m

We need to find the force with which two positive charges repel. It is called electrostatic force of repulsion. It can be given by :

$F=\dfrac{kq^2}{r^2}\\\\F=\dfrac{9\times 10^9\times (10^{-7})^2}{2^2}\\\\F=2.25\times 10^{-5}\ N$

So, the electric force of repulsion is $2.25\times 10^{-5}\ N$ .

8 0

2 years ago

Which form of energy is equal to the sum of an object’s kinetic and potential energy?

Natali5045456 [20]

Answer:

Mechanical Energy

Explanation:

The sum of kinetic energy and potential energy of an object is its total mechanical energy.

4 0

3 years ago

The exact speed of an object in a specific instant is?

GarryVolchara [31]

Im not so sure but it should be the
instantaneous speed

3 0

3 years ago

Read 2 more answers

Three charged particles are positioned in the xy plane: a 50-nC charge at y = 6 m on the y axis, a –80-nC charge at x = –4 m on

leva [86]

Answer:48 V

Explanation:

Given

Three charged particle with charge

$q_1=50\ nC at y=6\ m$

$q_2=-80\ nC at x=-4\ m$

$q_3=70\ nC at y=-6\ m$

Electric Potential is given by

$V=\frac{kQ}{r}$

Distance of $q_1$ from $x=8\ m$

$d_1=\sqrt{6^2+8^2}$

$d_1=\sqrt{36+64}$

$d_1=10\ m$

similarly $d_2=8-(-4)$

$d_2=12\ m$

$d_3=\sqrt{(-6)^2+8^2}$

$d_3=\sqrt{36+64}$

$d_3=10\ m$

Potential at $x=8\ m$ is

$V_{net}=\frac{kq_1}{d_1}+\frac{kq_2}{d_2}+\frac{kq_3}{d_3}$

$V_{net}=k[\frac{q_1}{d_1}+\frac{q_2}{d_2}+\frac{q_3}{d_3}]$

$V_{net}=9\times 10^9[\frac{50}{10}-\frac{80}{12}+\frac{70}{10}]\times 10^{-9}$

$V_{net}=9\times 5.33$

$V_{net}=47.97\approx 48\ V$

5 0

3 years ago

Explain what happens to light when it is refracted at the surface of water.

stepan [7]

Light will make the object appear “broken” or in an irregular shape.

Refraction is the change in direction of waves.

6 0

3 years ago

Read 2 more answers