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3 years ago

22 points! if right I will give brainlyest

Physics

2 answers:

hammer [34]3 years ago

8 0

<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ The dependent variable is the variable that is being measured.

In this case, the dependent variable is the amount of force required to stretch the spring.

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

Levart [38]3 years ago

4 0

A scientist suspends a spring from a force sensor. She then pulls on the spring causing the spring to stretch 1.0 cm. She records the amount of force applied to the spring. She then stretches the spring 2.0 cm and measures the new force. She repeats the process several times, each time increasing the length the spring is stretched.

The dependent variable in the experiment is the:

the length the spring is stretched

<u>the amount of force required to stretch the spring </u>

the weight of the spring

the force sensor

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A 60 kg person sits in a chair. How much does the earth pull on the person? (Acceleration due to gravity is -10m/s2) F = mxa → F

MA_775_DIABLO [31]

Answer:

<em>600N(downwards)</em>

Explanations

<em>600N(downwards)</em>

Mas of the person = 60kg

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To get the earths pull on the person, we will use the Newton second law of motion;

Force = mass * acceleration;

Force = 60 * -10

Force- -600N

<em>Hence the earth gravitational pull on the person is 600N(downwards). It is downwards due to the negative sign.</em>

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3 years ago

How fast is sound when traveling through water?

IgorLugansk [536]

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3 years ago

A housefly walking across a clean surface can accumulate a significant positive or negative charge. In one experiment, the large

nalin [4]

Answer:

1681714.28571 N/C

Yes it could exist

Explanation:

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q = Charge = 70 pC

g = Acceleration due to gravity = 9.81 m/s²

E = Electric field

When an object accumulates charge it means that it is gaining electrons making it negatively charged. This is the concept of static electricity.

Here, the electric force and the graviational force will balance each other

$F_e=W\\\Rightarrow qE=mg\\\Rightarrow E=\frac{mg}{q}\\\Rightarrow E=\frac{12\times 10^{-6}\times 9.81}{70\times 10^{-12}}\\\Rightarrow E=1681714.28571\ N/C$

1681714.28571 N/C of electric field would be required to levitate

The direction of the electric field would be upwards vertically.

In air the critical value of electric field is $3\times 10^6\ N/C$ which is more than the critical value of electric field in air. So, the electric field can exist.