Normal Force = 54 N
acceleration = 1.2 m/s^2
For Normal Force:
According to the force diagram, we can come up with the equation (all up and down forces):
10 sin 30 + Normal Force - 58.8 = 0
Normal Force = 53.8 N = 54 N
For acceleration:
According to the force diagram, we can come up with the equation (all left and right forces):
10 cos 30 - 1.5 = (6.0) (Acceleration)
Acceleration = 1.19 m/s^2 = 1.2 m/s^2
Answer:
These are the two statements with scientific facts that explain the described phenomenon
<span>
Gravitation between two objects increases when the distance between them decreases.</span>
When the mass of an object increases, its gravitational pull also increases.
Justification:
Those two facts are represented in the Universal Law of Gravity discovered by the scientific Sir Isaac Newton (1642 to 1727) and published in his book <span>Philosophiae naturalis principia mathematica.</span>
That law is represented by the equation:
F = G × m₁ × m₂ / d²
The product of the two masses on the numerator accounts for the fact that the gravitational force is directly proportional to the product of the masses, which is that as the masses increase the attraction also increase.
The term d² (square of the distance that separates the objects) in the denominator accounts for the fact that the gravitational force is inversely proportional to the square of the distance; that is as the separation of the objects increase the gravitational force decrease.
Newton's 2nd law of motion:
Force = (mass) x (acceleration)
= (0.314 kg) x (164 m/s²)
= 51.5 newtons
(about 11.6 pounds) .
Notice that the ball is only accelerating while it's in contact with the racket.
The instant the ball loses contact with the racket, it stops accelerating, and
sails off in a straight line at whatever speed it had when it left the strings.
Answer:
y = 12,000x + 40,000
Explanation:
A linear relationship that would model the mileage of the car in this example is:
where
y is the number of miles
x is the number of years
m is the number of miles driven per year
q is the number of miles already in the car at x=0
In this problem, we have
m = 12,000 (number of miles driven per year)
q = 40,000 (number of miles already in the car at x=0)
So substituting into the equation we get
1) 5765 mol
First of all, we need to find the volume of the gas, which corresponds to the volume of the room:
Now we can fidn the number of moles of the gas by using the ideal gas equation:
where
is the gas pressure
is the gas volume
n is the number of moles
R is the gas constant
is the gas temperature
Solving for n,
2) 184 kg
The mass of one mole is equal to the molar mass of the oxygen:
so if we have n moles, the mass of the n moles will be given by
since n = 5765 mol, we find
