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3 years ago

The vehicles are fitted with shockers why

1 answer:

7 0

Shockers acts as a shock absorber in the vehicle making the ride comfortable. When vehicle goes on rough road then it gets shocks from the road deformities the springs present in the shockers provide counter force and thus making the vehicle stable ride without shock.

[I copied this from the internet, but hope it helps!]

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How long does it take for a spaceship to get to the moon.

Ugo [173]

Answer:

about 3 days

It takes about 3 days for a spacecraft to reach the Moon. During that time a spacecraft travels at least 240,000 miles (386,400 kilometers) which is the distance between Earth and the Moon. The specific distance depends on the specific path chosen.

Explanation:

no explanation

8 0

2 years ago

Four identical particles of mass 0.514 kg each are placed at the vertices of a 4.70 m x 4.70 m square and held there by four mas

Alona [7]

In order to solve the problem it is necessary to take into account the concepts related to the moment of inertia, and the center of mass of the object.

Our values are given by:

m = 0.514kg

I = 4.7m (each side)

A) For the case when the axis passes through the midpoints of opposite sidesand lies in the plane of the square. The formula is given by,

$I = 4m (\frac{l}{2})^2\\I = 4*(0.514)(\frac{4.7}{2})^2\\I = 11.35kgm^2\\$

B) For the case when the axis passes through the midpoint of one of the sides and is perpendicular to the plane of the square. The formula is given by,

$I = 2m(\frac{l}{2})^2+2m(\frac{l}{2}^2+l^2)\\I = 2*(0.514)*(\frac{4.7}{2})^2+2*(0.514)*((\frac{4.7}{2})^2+4.7^2)\\I = 34.06Kgm^2$

C) For the case when the axis lies in the plane of square f passes through two diagonally opposite particles,

$I = \frac{1}{2}*l^2$

$I = \frac{1}{2}*(4.7)^2$

$I = 11.045kgm^2$

7 0

3 years ago

The normal force equals the magnitude of the gravitational force as a roller coaster car crosses the top of a 40-m-diameter loop

iogann1982 [59]

Answer:

Explanation:

Given

Diameter $d=40\ m$

radius $r=20\ m$

From diagram, at top point

If Normal force is equal to Gravitational force

$N=mg$

where N=normal reaction

m=mass of car

Normal reaction will provide centripetal force

$N=\frac{mv^2}{r}$

thus

$\frac{mv^2}{r}=mg$

$v=\sqrt{2gr}$

$v=\sqrt{2\times 9.8\times 20}$

$v=19.79\ m/s$

5 0

3 years ago

a swimmer can swim in still water at a speed of 9.50 m/s. he intends to swim directly across the river that has a downstream cur

Doss [256]

Refer to the diagram shown below.

Still-water speed = 9.5 m/s
River speed = 3.75 m/s down stream.

The velocity of the swimmer relative to the bank is the vector sum of his still-water speed and the speed of the river.

The velocity relative to the bank is
V = √(9.5² + 3.75²) = 10.21 m/s

The downstream angle is
θ = tan⁻¹ 3.75/9.5 = 21.5°

Answer: 10.2 m/s at 21.5° downstream.

7 0

4 years ago

Read 2 more answers

A water bug is suspended on the surface of a pond by surface tension (water does not wet the legs). The bug has six leg, and eac

Crazy boy [7]

Answer:

m = 2.2 x 10⁻⁴ kg = 0.22 g

Explanation:

The surface tension of water is 0.072 N/m. So in order for the bug to avoid sinking, its weight per unit length of contact must be no more than the surface tension of water. Therefore,

$Weight\ of bug\ per\ unit\ length = Surface\ Tension\ of\ Water\\\frac{mg}{L} = Surface\ Tension\ of Water\\m = \frac{(Surface\ Tension\ of\ Water)(L)}{g}$

where,

m = mass of bug = ?

g = acceleration due to gravity = 9.81 m/s²

L = Contact length = (contact length of each leg)(No. of Legs) = (5 mm)(6)

L = 30 mm = 0.03 m

Therefore,

$m = \frac{(0.072\ N/m)(0.03\ m)}{9.81\ m/s^{2}} \\$

8 0

3 years ago

The vehicles are fitted with shockers why​

The vehicles are fitted with shockers why