Question

You toss an apple horizontally at 9.5 m/s from a height of 1.8 m. Simultaneously, you drop a peach from the same height. How long does it take the peach to reach the ground?​

Answer 1

sorri no se _______________________________

Answer 2

Answer:

Peach and Apple will take the same time as the gravitional pull acting on both of them is equal.

height of peach=initial velocity*time+1/2*gravitional pull*(time^2)

1.8=0*time+1/2*9.8*time^2

1.8=0+1/2*9.8*time^2

1.8=1/2*9.8*time^2

3.6/9.8=time^2

taaking value of gravitional pull approx to 10

3.6/10=time^2

0.36=time^2

0.6=time

therefore, the time taken is 0.6sec

Explanation: