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Snowcat [4.5K]
3 years ago
8

Preschool girls and boys do not differ in the amount of muscle they have 1) True 2) False

Physics
1 answer:
Marina86 [1]3 years ago
3 0

Explanation:

False...............

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transmission electron microscopes that use high-energy electrons accelerated over a range from 40.0 to 100 kv are employed in ma
Gekata [30.6K]

The spatial limitations in Picometer for the given range of electrons would be around 50 picometers.

What is a transmission electron microscope?

A transmission electron microscope (TEM) is a type of microscope that uses a beam of high-energy electrons to produce detailed images of the structure of materials at the atomic or molecular scale. TEMs work by passing a focused beam of electrons through a thin sample and collecting the transmitted electrons on a fluorescent screen or an electronic detector. The interaction of the sample with the electrons results in the formation of an image that can be magnified and displayed on a computer monitor. TEMs are widely used in the fields of materials science, biology, and nanotechnology and can provide information about the structure, composition, and properties of materials with a high level and resolution.

According to the problem:

The spatial resolution of a transmission electron microscope (TEM) is determined by the size of the electron probe, which is directly related to the energy of the electrons. The higher the energy of the electrons is, the smaller the size of the probe is and the higher the spatial resolution.

At the lower end of the energy range of 40.0 kV, the spatial resolution of the TEM would be on the order of hundreds of nanometers. At the higher end of the range (100 kV), the spatial resolution would be on the order of tens of nanometers.

In general, TEMs with electron energy in the range of 40-100 kV are capable of resolving details down to around 50 picometers (pm). However, the actual spatial resolution will depend on various factors, such as the quality of the electron optics, the stability of the electron beam, and the sample preparation.

It's worth noting that TEMs with even higher electron energies (up to several hundred kV) are available, which can achieve spatial resolutions down to the sub-angstrom level (less than 0.1 pm). However, these instruments are much more expensive and complex to operate than TEMs with lower electron energies.

To know more about de broglie wavelength, visit:

brainly.com/question/17295250

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7 0
1 year ago
Pitch marks are the invitations left by the ball when they fall on the green
Kipish [7]
You can mark, lift and clean a ball on the green, but it's a violation to do so when another ball is in motion, as your ball might influence the outcome of that stroke. You can also mark and clean your ball in some instances when it's off the green: cleaning it, for example, just to the point where you can identify it.
3 0
3 years ago
Why are average temperatures higher at the equator than near the poles?
elena55 [62]
Bc the equator is constantly facing the sun while the earth rotates
3 0
3 years ago
Read 2 more answers
If a person climbed Mt. Everest has a mass of 105 kg and a weight of 625 N what would be the acceleration due to gravity?
DanielleElmas [232]

The acceleration due to gravity would be 5.95 m/s²

A force is known to be a push or pull and it is the change in momentum per time. It can be expressed by using the relation.

  • Force = mass × acceleration.

From the parameters given:

  • Mass = 105 kg
  • Force = 625 N

By replacing the given values into the above equation, we can determine the acceleration.

∴

625 N = 105 kg × acceleration.

\mathbf{acceleration = \dfrac{625 \ N}{105 \ kg}}

acceleration = 5.95 N/kg

  • Since 1 N/kg = 1 m/²

acceleration = 5.95 m/s²

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3 0
2 years ago
You have a grindstone (a disk) that is 90.0 kg, has a 0.340-m radius, and is turning at 90.0 rpm, and you press a steel axe agai
QveST [7]

Answer:

Explanation:

Given mass of grindstone m=90\ kg

radius of stone r=0.34\ m

angular speed of disc \omega =90\ rpm

Steel Axle applying a force of F=20\ N

coefficient of kinetic friction \mu =0.2

Frictional Torque applied by steel is given by

\tau=r\times f_r

\tau =r\times \mu F

where f_r=frictional force

\tau =r\times \mu \times F

\tau =0.34\times 0.2\times 20

\tau =1.36\ N-m

Torque is also given by

\tau =I\cdot \alpha

where \alpha=angular acceleration

I=moment of Inertia

\tau =0.5Mr^2\times \alpha

0.5Mr^2\times \alpha =1.36\ N-m

0.5\times 90\times 0.34^2\times \alpha =1.36

\alpha =0.261\ rad/s^2

3 0
3 years ago
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