Correct answer is A
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Answer:
π
Step-by-step explanation:
Solve for x on the interval [0, 2pi]
Given the equation
Sinx = cosx + 1
Square both sides of the equation
Sin²x = (cos x + 1)²
Sin²x = cos²x + 2cos x + 1
Since Sin²x = 1 - cos²x
1 - cos²x = cos²x + 2cos x + 1
Collect like terms
1-1-cos²x-cos²x-2cos x = 0
-2cos²x-2cos x = 0
-2cos²x = 2cos x
-cosx = 1
cos x = -1
x = arccos -1
x = 180 degrees
<em>Hence the value of x = π</em>
Step-by-step explanation:
There are infinitely many such integers.
x - y = -6 <em>add y to both sides</em>
x = -6 + y → x = y - 6
1. Choose any y value.
2. Substitute for the equation.
3. Calculate the value of x.
Examples:
for y = 0 → x = 0 - 6 = -6
check: -6 - 0 = -6
for y = 10 → x = 10 - 6 = 4
check: 4 - 10 = -6
for y = -9 → x = -9 - 6 = -15
check: -15 - (-9) = -15 + 9 = -6
The required zeroes are ~
Let's equate the given polynomial with 0, to find its roots ~
that is ~
there are two cases,
Case # 1 - when (x + √3) = 0
and
Case # 2 - when (x - √3) = 0
Answer:
d=3
Step-by-step explanation:
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