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zepelin [54]
3 years ago
5

A 14n force is applied for 0.33 seconds, calculate the impulse

Physics
1 answer:
Shalnov [3]3 years ago
5 0

Answer:

4.62 N-s

Explanation:

recall that the formula for impulse is given by

Impulse = Force x change in time

in our case, we are given

Force = 14 N

change in time = 0.33s

Simply substituting the above into the equation for impulse, we get

Impulse = Force x change in time

Impulse = 14 x 0.33

= 4.62 N-s

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Two vectors A and B are at right angles to each other. The magnitude of A is 3.00. What should be the length of B, so that the m
AfilCa [17]

Answer: length of B =4.00

Explanation:

for  the vectors A and B and the angle between them as  x.

Magnitude of the sum of A and B is  given as = √(A²+B²+2ABcosx

where

Magnitude of A  = 3.00

Magnitude of the sum of A and B is  5.00

5.00=√(A²+B²+2ABcos90°

5.00= √3² +b² +0

5²= 3² +b²

25=9+b²

b²= 25-9

b² = 16

b=  √16

b= 4

7 0
3 years ago
Which asteroid has more potential energy an asteroid that is closest to the sun or an asteroid that is farthest away from the su
Sloan [31]

When the comet is closest to the Sun,
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3 0
3 years ago
A parallel plate capacitor with plates of area A and plate separation d is charged so that the potential difference between its
faust18 [17]

Answer:

Explanation:

Given a parallel plate capacitor of

Area=A

Distance apart =d

Potential difference, =V

If the distance is reduce to d/2

What is p.d

We know that

Q=CV

Then,

V=Q/C

Then this shows that the voltage is inversely proportional to the capacitance

Therefore,

V∝1/C

So, VC=K

Now, the capacitance of a parallel plate capacitor is given as

C= εA/d

When the distance apart is d

Then,

C1=εA/d

When the distance is half d/2

C2= εA/(d/2)

C2= 2εA/d

Then, applying

VC=K

V1 is voltage of the full capacitor V1=V

V2 is the required voltage let say V'

Then,

V1C1=V2C2

V × εA/d=V' × 2εA/d

VεA/d = 2V'εA/d

Then the εA/d cancels on both sides and remains

V=2V'

Then, V'=V/2

The potential difference is half when the distance between the parallel plate capacitor was reduce to d/2

6 0
3 years ago
Read 2 more answers
Two narrow slits are illuminated by a laser with a wavelength of 593 nm. The interference pattern on a screen located x = 4.80 m
masya89 [10]

Answer:

The distance is  d =  1.39 *10^{-4} \  m

Explanation:

From the question we are told that

   The wavelength is  \lambda =  593 \ nm  =  593 *10^{-9} \ m

    The distance of the screen is   x  =  4.80 m

    The  location of the fourth order bright fringe is  y  =  8.20 cm = 0.082 m

    The order of the fringe is  n  =  4

   

Generally the position of a fringe with respect to the central fringe is mathematically represented as

           y  =  \frac{ n  *  x  *  \lambda }{d}

Where d is the distance between the slits, so making d the subject

          d =  \frac{\lambda  *  x  *  n }{ y }

substituting values

          d =  \frac{ 593 *10^{-9}  *  4.80  *  4 }{ 0.082 }

           d =  1.39 *10^{-4} \  m

7 0
3 years ago
1 point
Oduvanchick [21]
The distance it traveled is 147
5 0
3 years ago
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