The molarity of Ba(OH)₂ barium hydroxide solution is 0.41 M.
<h3>What is
Molarity ?</h3>
Molarity (M) is the amount of a substance in a certain volume of solution.
Molarity is defined as the moles of a solute per liters of a solution.
Molarity is also known as the molar concentration of a solution
It can be written as
The given data is
Mass of Ba(OH)₂ = 3 g
Volume of solution = 42.8 ml = 0.0428 l
Molecular weight of Ba(OH)₂ = 171 g
Moles of Ba(OH)₂ = 3/ 171 = 0.0175 moles
Molarity = 0.0175/0.0428
=0.41 M
Therefore the molarity of Ba(OH)₂ is 0.41 M.
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Answer:
1. Kc = [NO]⁴ [H₂O]⁶ / [NH₃]⁴ [O₂]⁵
2. Kc = [I₂]²
3. Kc = 1/[NH₃] [HCl]
Explanation:
The equilibrium constant (Kc) is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactant raised to their stoichiometric coefficients. It only includes gases and aqueous species.
1. 4 NH₃(g) + 5 O₂(g) ↔ 4 NO(g) + 6 H₂O(g)
Kc = [NO]⁴ [H₂O]⁶ / [NH₃]⁴ [O₂]⁵
2. ZrI₄(s) ↔ Zr(s) + 2 I₂(g)
Kc = [I₂]²
3. NH₃(g) + HCl(g) ↔ NH₄Cl(s)
Kc = 1/[NH₃] [HCl]
Answer:
9.64
Explanation:
pH + pOH = 14
Since pOH = 4.36, pH would be:
pH = 14 - pOH
pH = 14 - 4.36
pH = 9.64
Answer:
No of moles = mass / molar mass
Molar mass = 0.881/0.260
Molar mass = 5.51M
Explanation:
A diprotic acid is titrated with NaOH solution of known concentration. Molecular weight (or molar mass) is found in g/mole of the diprotic acid. Weighing the original sample of acid will tell you its mass in grams. Moles can be determined from the volume of NaOH titrant needed to reach the first equivalence point.
Answer:
distilling. since the liquids have different boiling points distilling would be the best.
