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Levart [38]
3 years ago
13

Plz help this is due today........

Chemistry
1 answer:
Jobisdone [24]3 years ago
4 0
A disease that targets any organism in the population with similar traits because more of the population live off of organisms if the organisms were to decrease then most of the population would decrease as well.
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Isotopes of the same element differ in their number of?
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Answer:

Neurons

Explanation:

Isotopes are atoms with different atomic masses which have the same atomic number. The atoms of different isotopes are atoms of the same chemical element; they differ in the number of neutrons in the nucleus.

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3 years ago
Can you please help me on my Chemistry homework.
Yanka [14]

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Explanation: i took the tet

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The direction of the electrochemical gradient for Na+ is:
qaws [65]

Answer:

B. the same as the concentration gradient for Na+

Explanation:

The net electrochemical gradient movement of potassium is to move into the cytoplasm of the cell, and the net electrochemical gradient of sodium is to move into the extracellular fluid. There is an overall negative net charge inside the cell than compared to the outside because of this

5 0
3 years ago
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Periods on the periodic table represent elements_____.
AlekseyPX
A period in the periodic table is a row of chemical elements. All elements in a row have the same number of electron shells
8 0
3 years ago
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The standard free-energy change for this reaction in the direction written is 23.8 kJ/mol. The concentrationsof the three interm
Natali [406]

Answer: The actual free-energy change for the reaction  -8.64 kJ/mol.

Explanation:

The given reaction is as follows.

  Fructose 1,6-bisphosphate \rightleftharpoons Glyceraldehyde 3-phosphate + DHAP

For the given reaction, \Delta G^{o} is 23.8 kJ/mol.

As we know that,

       \Delta G = \Delta G^{o} + RT ln Q

Here,    R = 8.314 J/mol K,       T = 37^{o} C

                                                    = (37 + 273) K

                                                    = 310.15 K

Fructose 1,6-bisphosphate = 1.4 \times 10^{-5} M

Glyceraldehyde 3-phosphate = 3 \times 10^{-6} M

DHAP = 1.6 \times 10^{-5} M

Expression for reaction quotient of this reaction is as follows.

    Reaction quotient = \frac{[DHAP][\text{glyceraldehyde 3-phosphate}]}{[/text{Fructose 1,6-bisphosphate}]}

        Q = \frac{1.6 \times 10^{-5} \times 3 \times 10^{-6}}{1.4 \times 10^{-5}}

            = 3.428 \times 10^{-6}

Now, we will calculate the value of \Delta G as follows.

          \Delta G = \Delta G^{o} + RT ln Q

                      = 23800 + 8.314 \times 310.15 \times ln(3.428 \times 10^{-6})

                      = -8647.73 J/mol

                      = -8.64 kJ/mol

Thus, we can conclude that the actual free-energy change for the reaction  -8.64 kJ/mol.

7 0
3 years ago
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