Question

How many grams of solute is there in 250 mL of a 0.10M CaCl2 solution ?

Answer 1

Answer:

2.775 g

Explanation:

Given that;

Number of moles = concentration × volume

Concentration = 0.10M

Volume =250 mL

Number of moles = 250/1000 × 0.10

Number of moles = 0.025 moles

Also;

Number of moles = mass/molar mass

Molar mass of CaCl2= 111 g/mol

Mass = Number of moles × molar mass

Mass = 0.025 moles × 111 g/mol

Mass= 2.775 g