The number of microorganisms that I will have after 10 days would be: 245.41 microoganisms.
<h3>How to calculate the number of microorganisms that I will have after 10 days?</h3>
To calculate the number of microorganisms that I will have after 10 days, I must perform the following operations:
We need to find 37% of 55 as shown below:
- 55 ÷ 100 = 0.55
- 0.55 x 37% = 20.35
- 55 + 20.35 = 75.35
So after 2 days I will have 75.35 microorganisms.
- 75.35 ÷ 100 = 0.75
- 0.7535 x 37% = 27.87
- 75.35 + 27.87 = 103.22
On the fourth day I will have: 103.22 microorganisms.
- 103.22 ÷ 100 = 1.0322
- 1.0322 x 37% = 38.19
- 103.22 + 38.19 = 141.41
On the sixth day I will have 141.41 microorganisms.
- 141.41 ÷ 100 = 1.4141
- 1.4141 x 37% = 52.32
- 141.41 + 52.32 = 193,73
On the eighth day I will have 193.73 microorganisms.
- 193.73 ÷ 100 = 1.9373
- 1.9373 x 37% = 71.68
- 193.73 + 71.68 = 265.41
On the tenth day I will have 245.41 microoganisms.
Learn more about percentages in: brainly.com/question/13450942
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Ummm let me see so what u have to do is
The way you can solve this is divide 38 by 5 to find out how many miles you run per minute. In this case, it would be 7.6. Now, for each minute you run, add 7.6 to it and you will have ran 7.5 miles.
Answer:
Step-by-step explanation:
Hi,
1) Find z if the standard normal curve area between -z and z is 0.4530.
Y1 = normalcdf(-x,x,0,1) - .4530 and x = .60226
a. ± 0.118
b. ± 0.398
c. ± 0.602 <==ANSWER
d. ± 0.752
2) If a random variable has the normal distribution with μ = 104.3 and σ = 5.7, find the probability that the value will be greater than 112.3
normalcdf(112.3, 500, 104.3, 5.7) = .08023
a. 0.08 <==ANSWER
b. 0.09
c. 0.10
d. 0.11
3) Determine a 90% confidence interval for μ if σ = 5, \bar{x} = 70, and n = 82. Answer interval rounded to two decimal places.
70 ± 1.645 (5/√82) or 69.09 to 70.91 <==ANSWER
I hope that helps!! :-)
