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2 years ago

Why is it important to have "alternate forms" of the periodic table?

Chemistry

1 answer:

fgiga [73]2 years ago

6 0

Answer:

so that you can see the different aspects of science

Explanation:

Alternate forms are useful because of the different aspects of the science that they illustrate - Carmen Giunta (a chemist at Le Moyne College in Syracuse, N.Y.)

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Molecular and empirical formulas

shepuryov [24]

Answer:

See below

Explanation:

Molecular formula ( just write down all of the elements ) C 4 H4 O4

Empiracle formual CHO

"Molecular formulas tell you how many atoms of each element are in a compound, and empirical formulas tell you the simplest or most reduced ratio of elements in a compound"

7 0

2 years ago

The half life for the first order conversion of A to B is 56.6 hours. How long does it take for the concentration of A to decrea

sveta [45]

Answer:

It will take 188.06 hours for the concentration of A to decrease 10.0% of its original concentration.

Explanation:

A → B

Initial concentration of the reactant = x

Final concentration of reactant = 10% of x = 0.1 x

Time taken by the sample, t = ?

Formula used :

$A=A_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}$

where,

$A_o$ = initial concentration of reactant

A = concentration of reactant left after the time, (t)

$t_{\frac{1}{2}}$ = half life of the first order conversion = 56.6 hour

$\lambda$ = rate constant

$A=A_o\times e^{-(\frac{0.693}{t_{1/2}})\times t}$

Now put all the given values in this formula, we get

$0.1x=x\times e^{-(\frac{0.693}{56.6 hour})\times t}$

t = 188.06 hour

It will take 188.06 hours for the concentration of A to decrease 10.0% of its original concentration.

4 0

3 years ago

Copper(II) sulfate pentahydrate, CuSO4 ·5 H2O, (molar mass 250 g/mol) can be dehydrated by repeated heating in a crucible. Which

prohojiy [21]

Answer:

The water lost is 36% of the total mass of the hydrate

Explanation:

Step 1: Data given

Molar mass of CuSO4*5H2O = 250 g/mol

Molar mass of CuSO4 = 160 g/mol

Step 2: Calculate mass of water lost

Mass of water lost = 250 - 160 = 90 grams

Step 3: Calculate % water

% water = (mass water / total mass of hydrate)*100 %

% water = (90 grams / 250 grams )*100% = 36 %

We can control this by the following equation

The hydrate has 5 moles of H2O

5*18. = 90 grams

(90/250)*100% = 36%

(160/250)*100% = 64 %

The water lost is 36% of the total mass of the hydrate

8 0

3 years ago

Which substance is not a structural isomer of hexyne?

stich3 [128]

Answer:

c) 3,3-dimethylpent-1-yne

5 0

3 years ago

Suppose you have a spherical balloon filled with air at room temperature and 1.0 atm pressure; its radius is 17 cm. You take the

Sladkaya [172]

Answer: 17.8 cm


Explanation:


1) Since temperature is constant, you use Boyle's law:


PV = constant => P₁V₁ = P₂V₂

=> V₁/V₂ = P₂/P₁

2) Since the ballon is spherical:

V = (4/3)π(r)³

Therefore, V₁/V₂ = (r₁)³ / (r₂)³


3) Replacing in the equation V₁/V₂ = P₂/P₁:

(r₁)³ / (r₂)³ = P₂/P₁

And you can solve for r₂: (r₂)³ = (P₁/P₂) x (r₁)³

(r₂)³ = (1.0 atm / 0.87 atm) x (17 cm)³ = 5,647.13 cm³

r₂ = 17.8 cm

4 0

3 years ago

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