Question 3

What is 6/10 simplified

Komok [63]

6/10 = 3/5

Simply divide the numerator and denominator of 6/10 by 2. 6/10 is the same as 3/5.

5 0

4 years ago

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Find the slope of a line parallel to this given line

dybincka [34]

bearing in mind that parallel lines have the same exact slope, then any parallel line to the one above will have the same slope as that one.

$\bf \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \qquad \implies y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{7}{3}}x-4$

3 0

3 years ago

6th grade math<br><br> help on numbers 4 5 6 plz help

mario62 [17]

Answer:

4) 6 students

5) 7 fewer students

6) No, you can not tell from the frequency table how many students ran a mile in exactly 12 minutes.

Step-by-step explanation:

4) you’d look at the row from 8:00-8:59.

5) Add the first two rows together (6+2=8), then subtract that by the sum of the last two rows (9+6=15), which is 7

6) There’s no pattern in the frequency table, and the data points would be plotted differently since it’d be from a range of times, not one set time.

Hope this helped, sorry if I’m wrong on #6 ;)

6 0

3 years ago

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WILL GIVE BRAINLIEST AND 30 POINTS! Peter calculated |5 + 13i| by finding Where was Petey’s mistake? He should not have used the

tiny-mole [99]

Answer: He should have used 13 instead of 13i

Step-by-step explanation:

5 0

3 years ago

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Find the lengths and slopes of the diagonals to name the parallelogram. Choose the most specific name. E (-2, -4), F(0, -1), G(-

Kay [80]

Answer:

1) d) Square

2) Proofs that PWRS is a rhombus are

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Step-by-step explanation:

The given points (x, y) of the parallelogram are;

E(-2, -4), F(0, -1), G(-3, 1), H(-5, -2)

The slope, m, of the segments are found as follows;

$Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$

By computation, the slope of segment EF = 1.5

The slope of segment FG = -0.67

The slope of segment GH = 1.5

The slope of segment HE = -0.67

Therefore, EF is parallel to GH and FG is parallel to HE

The length of the sides are;

$\sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$

By computation, the length of segment EF = 3.61

The length of segment FG = 3.61

The length of segment GH = 3.61

The length of segment HE = 3.61

The diagonals are;

EG and FH

The length of segment EG = 5.099

The length of segment FH = 5.099

Therefore, the diagonals are equal and the parallelogram is a square

2) The given dimensions are;

P(-1, 3), Q(-2, 5), R(0, 4), S(1, 2)

A rhombus has all sides equal

The length of segment PQ = 2.24

The length of segment QR = 2.24

The length of segment RS = 2.24

The length of segment PS = 2.24

The diagonals are;

QS and PR

The length of segment QS = 4.24

The length of segment PR = 1.41

The slope of segment QR = -0.5

The slope of segment PS = -0.5

The slope of segment RS = -2

The slope of segment QP = -2

Therefore, QS≠QR the parallelogram is a rhombus

The correct option ;

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Where there are acute angles in parallelogram PQRS, then the correct option is d) Length of QR and PS is 2.2 and Length of RS and QP is 2.2

8 0

3 years ago