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lora16 [44]
3 years ago
15

Which shows the correct order of events during the process of nucleosynthesis?

Chemistry
2 answers:
horrorfan [7]3 years ago
5 0

Answer:

hydrogen nucleus formed, isotope of hydrogen, trítium formed, helium nucleus formed

Explanation:

Nucleosynthesis is the process which took place within few minutes of formation of universe . In this process initial lighter elements were formed from hydrogen atoms . The correct chronology is as follows .

1 ) Hydrogen nucleus

2 ) Deuterium

3 ) Tritium

4) Helium nucleus .

Vlad1618 [11]3 years ago
3 0

Answer:

A) hydrogen nucleus formed, isotope of hydrogen, tritium formed, helium nucleus formed

Explanation:

edge

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Find 3.2458+1.221+4.45
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Typically, the hydrogen gas is bubbled through water for col- lection and becomes saturated with water vapor. Suppose 240. mL of
klio [65]

Answer:PH2=0.994atm, mass of zinc=0.606g

Explanation:

Equation for the reaction is written as;

Zn(s) + 2HCl(aq) - ZnCl2(aq) + H2(g)

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T= 30.8oC = 303.8K

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3 0
3 years ago
Write the net ionic equation for any precipitation reaction that may be predicted when aqueous solutions of calcium iodide and c
Hitman42 [59]

<u>Answer:</u> The net ionic equation is written below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of calcium iodide and chromium (III) sulfate is given as:

3CaI_2(aq.)+Cr_2(SO_4)_3(aq.)\rightarrow 3CaSO_4(s)+2CrI_3(aq.)

Ionic form of the above equation follows:

3Ca^{2+}(aq.)+6I^{-}(aq.)+2Cr^{3+}(aq.)+3SO_4^{2-}(aq.)\rightarrow 3CaSO_4(s)+2Cr^{3+}(aq.)+6I^-(aq.)

As, chromium and iodide ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

3Ca^{2+}(aq.)+3SO_4^{2-}(aq.)\rightarrow 3CaSO_4(s)

Hence, the net ionic equation is written above.

8 0
3 years ago
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