Answer : The energy required to melt 58.3 g of solid n-butane is, 4.66 kJ
Explanation :
First we have to calculate the moles of n-butane.
Given:
Molar mass of n-butane = 58.12 g/mole
Mass of n-butane = 58.3 g
Now put all the given values in the above expression, we get:
Now we have to calculate the energy required.
where,
Q = energy required
= enthalpy of fusion of solid n-butane = 4.66 kJ/mol
n = moles = 1.00 mol
Now put all the given values in the above expression, we get:
Thus, the energy required to melt 58.3 g of solid n-butane is, 4.66 kJ
Answer:
Their electrons are placed in a higher number of orbitals
Explanation:
- Suppose a element be Ga .
The atomic no is 31
The configuration is given by
Or
![\\ \sf\longmapsto [Ar]3d^{10}4s^24p^1](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%5BAr%5D3d%5E%7B10%7D4s%5E24p%5E1)
<span>The answer is Cs, no. 2.
Cesium (Cs) is an element which has an outermost electron with most energy in
the ground state.</span>
Cesium (Cs), Lithium (Li), Potassium
(K), and Sodium (Na) are elements which belong to the group 1 family, the
alkali metals. Each has a valance of 1 and wants to release/ lose this e-
(electron) to be isoelectronic with the nearest noble gas. Based on the
periodic trends, an atom’s radii will raise going down a group.
Answer:
The right answer to this is (b)
