Question

When barium hydroxide reacts with sulfuric acid, barium sulfate and water are produced. The balanced equation for this reaction is: Ba(OH)2 (aq) H2SO4 (aq) BaSO4 (s) 2H2O (l)

Answer 1

Answer: The balanced equation for given reaction is $Ba(OH)_{2}(aq) + H_{2}SO_{4}(aq) \rightarrow BaSO_{4}(s) + 2H_{2}O(l)$.

Explanation:

A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.

For example, $Ba(OH)_{2}(aq) + H_{2}SO_{4}(aq) \rightarrow BaSO_{4}(s) + 2H_{2}O(l)$

Number of atoms on reactant side are as follows.

• Ba = 1
• O = 6
• H = 4
• S = 1

Number of atoms on product side are as follows.

• Ba = 1
• O = 6
• H = 4
• S = 1

Since atoms on both reactant and product side are equal. Therefore, this equation is balanced.

Thus, we can conclude that balanced equation for given reaction is $Ba(OH)_{2}(aq) + H_{2}SO_{4}(aq) \rightarrow BaSO_{4}(s) + 2H_{2}O(l)$.