Answer:
Its a social media platform
Explanation:
Answer:
3.83 m/s
Explanation:
Given that,
Distance covered by Jan, d = 4 miles
1 mile = 1609.34 m
4 miles = 6437.38 m
Time, t = 28 minutes = 1680 s
Jan's average speed,
v = d/t

Hence, the average velocity of Jan is 3.83 m/s.
We have that the speed over the ground of a mosquito flying 2 m/s relative to the air against a 2 m/s headwind is
X=0m/s
From the question we are told that
mosquito flying 2 m/s
against a 2 m/s headwind
Generally
The speed over the ground is the Flight Speed minus resistance speed
Generally the equation for the speed over the ground is mathematically given as
X=Flight Speed-resistance speed
Therefore
X=2-2
X=0m/s
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Answer:
Point a
Explanation:
The potential energy of an object is given by :
P = mgh
m is mass, g is acceleration due to gravity, h is height above ground level.
Potential energy is directly proportional to the position of an object.
In the attached figure, the maximum height is shown at point (a). It means it will have maximum potential energy at a as compared to b,c and d.
Answer - B. Betelguese.
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