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olga55 [171]
3 years ago
15

Place the gears in order from highest to lowest torque?

Physics
1 answer:
Trava [24]3 years ago
5 0
60, 12, 24,48- ddfjjvdd
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A careful photographic survey of Jupiter's moon Io by the spacecraft Voyager 1 showed active volcanoes spewing liquid sulfur to
Over [174]

The concept used to solve this problem is that given in the kinematic equations of motion. From theory we know that the change in velocities of a body is equivalent to twice the distance traveled by acceleration, in other words:

v_f^2-v_i^2 = 2ax

Where,

v_{f,i} = Final and initial velocity

a = Acceleration

x = Displacement

For the given case, the displacement is equivalent to the height (x = h) and the acceleration is the same gravitational acceleration (a = g). In turn we do not have initial speed therefore

v_f^2 = 2hg

v_f = \sqrt{2hg}

Our values are given as

h = 70km = 70*10^3m

g = 2m/s^2

Replacing we have that,

v_f = \sqrt{2hg}

v_f = \sqrt{2(70*10^3)(2)}

v_f = 529.15m/s

Therefore the speed with which the liquid sulfur left the volcano is 529.15m/s

6 0
3 years ago
1. Mean Billy is standing on a bridge, waiting for his sister to walk underneath so that he can drop his vanilla ice cream cone
vovikov84 [41]

Answer:

fdghgjkk , mmn xgwvdkqgeb e keqwkclhehjq  qbqlq.bq;q

Explanation:

8 0
3 years ago
A car accelerates at a rate of 13m/s^2[S]. If the car's initial velocity is 120km/h[N]. What will be its final velocity in m/s,
balu736 [363]

Answer:

the final velocity of the car is 59.33 m/s [N]

Explanation:

Given;

acceleration of the car, a = 13 m/s²

initial velocity of the car, u = 120 km/h = 33.33 m/s

duration of the car motion, t = 2 s

The final velocity of the car in the same direction is calculated as follows;

v = u + at

where;

v is the final velocity of the car

v = 33.33 + 13 x 2

v = 59.33 m/s [N]

Therefore, the final velocity of the car is 59.33 m/s [N]

4 0
3 years ago
What is the minimum mass needed for a star to be on the main sequence? What happens to stars that do not meet the minimum mass?
Mariana [72]
Main sequence stars are characterised by the source of their energy.They are all undergoing fusion of hydrogen into helium within their cores. The mass of the star is the main element for such process or phenomenon to take place for it is a determinant of both the rate at which they perform the said activity and the amount of fuel available. 

To answer the question, the lower mass limit for a main sequence star is about 0.08. If the mass of a main sequence star is lower than the above-mentioned value, there would be a deficit or insufficiency of gravitational force to generate a standard temperature for hydrogen core fusion to take place and the underdeveloped star would form into a brown dwarf instead.
6 0
3 years ago
A satellite originally moves in a circular orbit of radius R around the Earth. Suppose it is moved into a circular orbit of radi
sergiy2304 [10]

 satellite originally moves in a circular orbit of radius R around the Earth. Suppose it is moved into a circular orbit of radius 4R.

(i) What does the force exerted on the satellite then become?

eight times larger<span>four times larger   </span>one-half as largeone-eighth as largeone-sixteenth as large(ii) What happens to the satellite's speed?<span>eight times larger<span>four times larger   </span>one-half as largeone-eighth as largeone-sixteenth as large(iii) What happens to its period?<span>eight times larger<span>four times larger   </span>one-half as largeone-eighth as largeone-sixteenth as large</span></span>
<span>
</span>
3 0
3 years ago
Read 2 more answers
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