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Charra [1.4K]
3 years ago
7

If you climb two sets of stairs each with a height of 4 meters how much work will you do compared to climbing just one set of st

airs that is 4 meters
Physics
1 answer:
Firlakuza [10]3 years ago
3 0

Answer:

You will do twice the work of climbing 1 stair.

Explanation:

To obtain the answer to the question, we shall determine the work done on each case. This is illustrated below:

Case 1 ( climbing 2 stairs):

Mass (m) = m

One stair = 4 m

Height (h) = 2 × 4 = 8 m

Acceleration due to gravity (g) = 10 m/s²

Workdone 1 (Wd₁) =?

Wd₁ = mgh

Wd₁ = m × 10 × 8

Wd₁ = 80 × m

Case 2 (Climbing 1 stair)

Mass (m) = m

Height (h) = 4 m

Acceleration due to gravity (g) = 10 m/s²

Workdone 2 (Wd₂) =?

Wd₂ = mgh

Wd₂ = m × 10 × 4

Wd₂ = 40 × m

Now comparing the Workdone in both case:

Workdone 1 (Wd₁) = 80 × m

Workdone 2 (Wd₂) = 40 × m

Wd₁ / Wd₂ = 80 × m / 40 × m

Wd₁ / Wd₂ = 2

Cross multiply

Wd₁ = 2 × Wd₂

Thus, we can see that the Workdone in climbing 2 stairs is twice the Workdone in climbing 1 stair.

Therefore, you will do twice the work of climbing 1 stair.

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Answer:

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a=\frac{F}{m}

Having seen Newton's second law it should be clear that the particles are actually moving away from each other and will not remain at rest with respect to each other. This is in contradiction with the last statement in the problem.

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2 years ago
The scientific method is
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What would be the speed of an object just before hitting the ground if dropped 91.5 meters
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Answer:

about 42.35 m/s

Explanation:

Use the equation for accelerated motion (g), and with zero initial velocity that doesn't include time:

v_f^2=v_i^2+2\,a\,\Delta x

which for our case would reduce to:

v_f^2=v_i^2+2\,a\,\Delta x\\v_f^2=0+2\,9.8\,(91.5)\\v_f^2= 1793.4\\v_f=\sqrt{1793.4} \\v_f \approx 42.35

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5 0
3 years ago
How fast would you be going (in kmh) if you had a ship that accelerated at a constant 1g for 24 hours?
Nady [450]

Answer:

Explanation:

1 g is 9.8 m/s^2 the problem wants the results in km/h so we'll fix that really quick.

9.8 m/s^2 (1 km/1000m)(60 sec/1 min)^2(60 min/1 hour)^2 = 127008 km/hour^2

Now, I'm assuming the ship is starting from rest, and hopefully you know your physics equations.  We are going to use vf = vi + at.  Everything is just given, or we can assume, so I'll just solve.

vf = vi + at

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A Shaolin monk of mass 60 kg is able to do a ‘finger stand’: he supports his whole weight on his two index fingers, giving him a
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Answer:

1500000 Pa

Explanation:

The formula for pressure is force per unit area.

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P= 1471500

P=1500000 Pa

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3 years ago
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